max(start1, start2)<min(end1, end2)就相交了

處理兩個(gè)事件是否有重合的時(shí)間

        for d in declined_list:  # 循環(huán) 事件列表a
            limit_start = d.start  # 事件A開始時(shí)間戳
            limit_end = d.end  # 時(shí)間A結(jié)束時(shí)間戳
            for n in normal_list: # 循環(huán)事件列表b
                start = n.start   # 事件B開始時(shí)間時(shí)間戳
                end = n.end  # 事件B結(jié)束時(shí)間時(shí)間戳
                if min(end, limit_end) - max(start, limit_start) > 5 * 60:
                    d.updated_status = 'declined'
                    d.save()
                    break