[LeetCode]122. Best Time to Buy and Sell Stock II

題目

Say you have an array for which the ith element is the price of a given stock on day i.

Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).

c代碼
#include <assert.h>

int maxProfit(int* prices, int pricesSize) {
    int i = 0;
    int profit = 0;
    for(i = 0; i < pricesSize-1; i++) {
        if(prices[i+1] > prices[i])
            profit += prices[i+1]-prices[i];
    }
    return profit;
}

int main() {
    int prices[5] = {1,5,3,9,2};
    assert(maxProfit(prices, 5) == 10);

    return 0;
}
最后編輯于
?著作權(quán)歸作者所有,轉(zhuǎn)載或內(nèi)容合作請聯(lián)系作者
【社區(qū)內(nèi)容提示】社區(qū)部分內(nèi)容疑似由AI輔助生成,瀏覽時(shí)請結(jié)合常識(shí)與多方信息審慎甄別。
平臺(tái)聲明:文章內(nèi)容(如有圖片或視頻亦包括在內(nèi))由作者上傳并發(fā)布,文章內(nèi)容僅代表作者本人觀點(diǎn),簡書系信息發(fā)布平臺(tái),僅提供信息存儲(chǔ)服務(wù)。

相關(guān)閱讀更多精彩內(nèi)容

友情鏈接更多精彩內(nèi)容