1,當(dāng)鍵盤為中文輸入法時(shí),移除聯(lián)想時(shí)中間的空格字符
<pre><code>
正則表達(dá)式 \w \s \d \b 2012-09-19 22:21:49
分類： Python/Ruby

正則表達(dá)式 \w \s \d \b
. 匹配除換行符以外的任意字符
\w 匹配字母或數(shù)字或下劃線或漢字 等價(jià)于 '[^A-Za-z0-9_]'。
\s 匹配任意的空白符
\d 匹配數(shù)字
\b 匹配單詞的開始或結(jié)束
^ 匹配字符串的開始
$ 匹配字符串的結(jié)束
\w能不能匹配漢字要視你的操作系統(tǒng)和你的應(yīng)用環(huán)境而定
</code></pre>

<pre><code>

• (NSString *) removeWhitespace
  {
  return [self stringByReplacingOccurrencesOfString:@"\s" withString:@""
  options:NSRegularExpressionSearch
  range:NSMakeRange(0, [self length])];
  }
  </code></pre>

2,過濾Emoji
<pre><code>

• (NSString*)removeEmojiWithInputString :(NSString )str {
  __block NSMutableString temp = [NSMutableString string];

  [str enumerateSubstringsInRange: NSMakeRange(0, str.length) options:NSStringEnumerationByComposedCharacterSequences usingBlock:
  ^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop){

     const unichar hs = [substring characterAtIndex: 0];
     
     // surrogate pair
     if (0xd800 <= hs && hs <= 0xdbff) {
         const unichar ls = [substring characterAtIndex: 1];
         const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
         
         [temp appendString: (0x1d000 <= uc && uc <= 0x1f77f)? @"": substring]; // U+1D000-1F77F
         
         // non surrogate
     } else {
         [temp appendString: (0x2100 <= hs && hs <= 0x26ff)? @"": substring]; // U+2100-26FF
     }
  

  }];

  return temp;
  }
  </code></pre>