由下面的數(shù)據(jù)

image

生成

image

create table tmp_access(
name string,
mon string,
num int
); 

insert into table tmp_access 
select uname,umonth,sum(ucount)
 from t_access t group by t.uname,t.umonth;

create view tmp_view as 
select a.name anme,a.mon amon,a.num anum,b.name bname,b.mon bmon,b.num bnum from tmp_access a join tmp_access b 
on a.name=b.name;

select anme,amon,anum,max(bnum) as max_access,sum(bnum) as sum_access 
from tmp_view 
where amon>=bmon 
group by anme,amon,anum;