在左右兩側(cè)欄目下，

????????左側(cè)? ?|? ?右側(cè)

如欄目ID=3下的文章，分別調(diào)用 12篇文章，

那么在需要的欄目下調(diào)用文章：

左側(cè)： [e:loop={3,12,0,0,'','newstime DESC'}]

右側(cè)：[e:loop={3,'12,12',0,0,'','newstime DESC'}]

注釋：右側(cè)想調(diào)取第13篇文章的話，那么右側(cè)的第一個(gè)數(shù)字應(yīng)該是12，而不是13

結(jié)合應(yīng)用思考：

是不是可以結(jié)合if判斷 將這塊html進(jìn)行做判斷呢？

if{

?[e:loop={3,12,0,0,'','newstime DESC'}]

????????????if{

? ?????????[e:loop={2,1,0,0,'isgood=1','newstime DESC'}]

????????????}

????????else{

? ??????????[e:loop={3,12,0,0,'','newstime DESC'}]

? ? ? ? ?}

}

else{

[e:loop={3,'12,12',0,0,'','newstime DESC'}]

????????if{

????????[e:loop={2,1,0,0,'isgood=1','newstime DESC'}]

????????}

? ? ? ? else{

????????[e:loop={3,'12,12',0,0,'','newstime DESC'}]

????????}

}