需求：R1，R2，R3均為3個(gè)元素的列表，對(duì)應(yīng)元素相加，需要滿足關(guān)系R1+R2=R3。分別給定3組R1,R2,R3的可能取值的絕對(duì)值，通過(guò)改變這些值的符號(hào)，使得滿足R1+R2=R3.

• 完整代碼：

# ************************************************************************
# _*_coding:utf-8_*_
# Author: Pandas120 （微信）
# Desription: R1，R2，R3均為3個(gè)元素的列表，對(duì)應(yīng)元素相加，需要滿足關(guān)系R1+R2=R3。分別給定3組R1,R2,R3的可能取值的絕對(duì)值，通過(guò)改變這些值的符號(hào)，使得滿足R1+R2=R3.
# ************************************************************************

def new_value(R_value):
    new_list = []
    range_value = [1,-1]
    for value in R_value:
        for i in range_value:
            for j in range_value:
                for k in range_value:
                    value1 = [xx*yy for xx,yy in zip([i,j,k],value)]
                    if value1 not in new_list:
                        new_list.append(value1)
    return new_list


if __name__=="__main__":
    abs_values_R1 = [[1, 2, 1], [2, 2, 1], [1, 4, 1]]
    abs_values_R2 = [[1, 0, 1], [0, 2, 1], [1, 2, 1]]
    abs_values_R3 = [[1, 0, 2], [0, 2, 2], [1, 2, 2]]
    abs_values_R1 = new_value(abs_values_R1)
    abs_values_R2 = new_value(abs_values_R2)
    abs_values_R3 = new_value(abs_values_R3)

    data = ['R1_1,R1_2,R1_3,R2_1,R2_2,R2_3,R3_1,R3_2,R3_3']
    for r1_value in abs_values_R1:
        for r2_value in abs_values_R2:
            for r3_value in abs_values_R3:
                if [i + j for i, j in zip(r1_value, r2_value)]  ==r3_value:
                    res = ",".join([str(x) for x in r1_value+ r2_value+r3_value])
                    data.append(res)
    if len(data)==1:
        print('沒(méi)有匹配的結(jié)果！！')      
    else:        
        outstr = "\n".join(data)
        with open('res.csv','w') as f:
            f.write(outstr)