上傳表單的按鈕如果是button，需要把類型定為button，否則form表單就不會(huì)通過ajax程序傳輸數(shù)據(jù)，

因?yàn)樗哪J(rèn)類型是submit，

ajax代碼：表單中每條數(shù)據(jù)的name值要和數(shù)據(jù)表中的字段名一致

$(function(){

????$('#f_add').click(function(){

????????var url = "{:U('Fink/add')}";

????????var formObj = $('form');

????????var data = formObj.serialize();

????????$.post(url,data,function(r){

????????????if(r.status == 200){

????????????????alert(r.msg);

????????????????window.location.href = "{:U('Fink/index')}";

????????????????}else{

???????????????alert(r.msg);

? ? ? ? ? ? ?}

????????},'json');

????});

});

后臺(tái)代碼：

function add(){

if(IS_POST){

$data = I('post.');

// dump($info);die;

$fink = M('Fink');

if($fink->add($data)){

$data['status'] = 200;

$data['msg'] = '添加成功';

$this->ajaxReturn($data);

}else{

$data['status'] = 400;

$data['msg'] = '添加失敗';

$this->ajaxReturn($data);

}

}else{

$this->display();

}

}