解析xml格式文件(不用第三方庫(kù)函數(shù))

題目:

將下面xml格式文件,按樹(shù)狀結(jié)構(gòu)進(jìn)行輸出,格式如書(shū)本目錄,條件是不能用第三方庫(kù),比如什么dom,sax,pull解析方式,一句話(huà),把里面的節(jié)點(diǎn)自己慢點(diǎn)摳出來(lái)吧。
(純屬自?shī)首詷?lè),有問(wèn)題的地方或者有更好的想法,歡迎交流,謝謝,qq:413686520)

<people  >
    <person id="001">  
        <name>XY1</name>  
        <age>22</age>  
    </person>

    <name key1="fsefsef" key2="gdrhr" />
    <person id="002">  
        <name>XY2</name>
        <age>22</age>
        <grade>
            <math>98</math>
            <english>100</english>
            <music>28</music>
        </grade>
    </person>
    <wenzhang key1="fsefsef" key2="gdrhr" />
    <life key1="fsefsef" key2="gdrhr" />

</people>

對(duì)于這個(gè)題目,最開(kāi)始我對(duì)出題人的要求搞錯(cuò)了,以為只要節(jié)點(diǎn)名字,節(jié)點(diǎn)深度,最后輸出成目錄結(jié)構(gòu)就行。所以,我就悲劇了,我最開(kāi)始是用in.read()一個(gè)一個(gè)讀到內(nèi)存中,按字符來(lái)解析的,可以想象一下最后是多么艱難的寫(xiě)出來(lái)的,花了4個(gè)小時(shí),可能時(shí)間更長(zhǎng),早上沒(méi)有吃飯,寫(xiě)完的時(shí)候,已經(jīng)餓的肚子疼了。一個(gè)字符一個(gè)字符的解析,竟然讓我搞出來(lái)了。最開(kāi)始的想法決定了算法最終的難度。下面給出這兩天重新寫(xiě)過(guò)后的結(jié)果:

圖片.png

其中,我們拿grade節(jié)點(diǎn)說(shuō)明一下,它的節(jié)點(diǎn)深度為3,它有孩子節(jié)點(diǎn)mat,h,english,music,其他的節(jié)點(diǎn)可能還存在key:value鍵值對(duì)等等(直接看圖吧)。

思路:

首先,一次讀取一行,并且從讀取的內(nèi)容中找到第一個(gè)右括號(hào)‘>’,這樣我們最后需要處理的內(nèi)容都會(huì)變?yōu)槿缦聨追N形式:

(1).***<******>
(2).***<******/>
(3).***</******>

注意:先規(guī)定下本文節(jié)點(diǎn)的格式
例如


圖片.png

對(duì)于上面的三種狀態(tài),對(duì)于‘<’左邊的只可能是節(jié)點(diǎn)的text文本值,然后對(duì)于“<>”,里面只可能是節(jié)點(diǎn)名字,鍵值對(duì),節(jié)點(diǎn)結(jié)束標(biāo)志。

首先構(gòu)建我們的節(jié)點(diǎn),如下所示:

package com.lifestudy.stdy.lifestudy.readxml;

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

/**
 * Created by lj on 2017/6/16.
 */

public class LjXMLNode {
    int id;//唯一標(biāo)識(shí)
    String name;//節(jié)點(diǎn)的名字
    List<Integer> children = new ArrayList();//當(dāng)前節(jié)點(diǎn)的孩子節(jié)點(diǎn)
    int parent = -1;//默認(rèn)父節(jié)點(diǎn),用id表示
    Map<String,String> mapKeyValue = new HashMap();//當(dāng)前節(jié)點(diǎn)的key:value
    String text="";//當(dāng)前節(jié)點(diǎn)的文本值
    int level;//當(dāng)前節(jié)點(diǎn)的深度
}

然后,開(kāi)始開(kāi)始遍歷我們的xml文件:

public void readXMLFile(InputStream inputStream){
        try {
            InputStreamReader inputStreamReader = new InputStreamReader(putStream);
            BufferedReader in = new BufferedReader(inputStreamReader);
            System.out.println("開(kāi)始輸入:");
            StringBuffer sb = new StringBuffer();
            String s;
            String rest = "";
            while( ( s = in.readLine() ) != null ){
                s = s.trim();
                s = rest + s;

                int start = 0;
                for( int i = 0; i < s.length(); i++ ){
                    if( s.charAt(i) == '>'){
                        process(s.substring(start,i+1));
                        start = i + 1;
                    }
                }
                if( start >= s.length() ){//說(shuō)明處理到最後一個(gè)字符了
                    //do nothing
                }else{
                    rest = s.substring(start,s.length());
                }
            }
//            System.out.println( sb.toString() );
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

然后,在process()方法中處理最開(kāi)始的三種情況:
說(shuō)明:對(duì)于'<'左邊的字符都是節(jié)點(diǎn)的text值,對(duì)于‘<’右邊的第一個(gè)單詞肯定是節(jié)點(diǎn)的name,當(dāng)我們讀取完name時(shí),我們創(chuàng)建一個(gè)LjXMLNode節(jié)點(diǎn)node,賦值node.name,最后,入棧的并將其父節(jié)點(diǎn)node.parent指向棧頂元素,同時(shí)讓棧頂元素的孩子節(jié)點(diǎn)加1。然后是讀取節(jié)點(diǎn)的key:value(這個(gè)可以根據(jù)是否有等號(hào)來(lái)判斷),并且更新node的值。最后當(dāng)前節(jié)點(diǎn)只可能以右括號(hào)'>'或者'/>'兩種形式結(jié)尾,當(dāng)我們讀取到“/”時(shí),將當(dāng)前節(jié)點(diǎn)出棧(同時(shí),如果想對(duì)節(jié)點(diǎn)做操作,也是在出棧時(shí),因?yàn)槌鰲5墓?jié)點(diǎn)元素是完整的,它肯定是遍歷完成了,本文是將出棧的元素保存到一個(gè)map中了,其中key是id,value是LjXMLNode)。

/**
     * 處理
     * 主要是對(duì)stack的操作
     */
    private void process(String s){

        String nodeName = "";
        String text = "";

        for( int i = 0; i < s.length();i++ ){
            if( s.charAt(i) == '<'){

                text = s.substring(0,i);
                if( mStack.size() > 0){
                    LjXMLNode topNode = mStack.peek();
                    topNode.text = text;
                }

                if( s.charAt(i+1) != '/'){

                    nodeName = findNodeName(s.substring(i+1));
                    //push
                    LjXMLNode node = new LjXMLNode();
                    node.id = ID_0++;
                    node.name = nodeName;
                    if( mStack.size() > 0){
                        LjXMLNode parentNode = mStack.peek();
                        node.parent = parentNode.id;
                        parentNode.children.add(node.id);
                    }
                    mStack.push(node);

                    for( int j = i+1; j < s.length();j++ ){
                        if( s.charAt(j) == '='){//key:value
                            String key = findFirstLeftWord(s,j);
                            String value = findFirstRightWord(s,j);
                            if( key != ""){
                                LjXMLNode curNode = mStack.peek();
                                curNode.mapKeyValue.put(key,value);
                            }
                        }
                    }

                    for( int j = i+2; j < s.length();j++ ){
                        if( s.charAt(j) == '/'){
                            LjXMLNode shuchuNode =  mStack.pop();
                            shuchuNode.level = mStack.size() + 1;
                            mFinalNodes.put(shuchuNode.id,shuchuNode);
                            System.out.println("shuchuNode:" + "id:"+shuchuNode.id + " name:"+shuchuNode.name
                                    + " key_count:"+shuchuNode.mapKeyValue.size()
                                    + " text:" + shuchuNode.text
                                    +"  parent:"+ shuchuNode.parent);
                        }
                    }

                }else {
                    //pop
                    LjXMLNode shuchuNode =  mStack.pop();
                    shuchuNode.level = mStack.size() + 1;
                    mFinalNodes.put(shuchuNode.id,shuchuNode);
                    System.out.println("shuchuNode:" + "id:"+shuchuNode.id + " name:"+shuchuNode.name
                            + " key_count:"+shuchuNode.mapKeyValue.size()
                            + " text:" + shuchuNode.text
                            +"  parent:"+ shuchuNode.parent);
                }
                break;
            }
        }
    }

最后是對(duì)節(jié)點(diǎn)的遍歷,因?yàn)樘幚砗蟮墓?jié)點(diǎn),最后會(huì)存儲(chǔ)為成森林的樹(shù)狀結(jié)構(gòu),如下所示:

圖片.png

所以,這塊采用樹(shù)的深度優(yōu)先遍歷算法。思想很簡(jiǎn)單,構(gòu)建一個(gè)棧結(jié)構(gòu),首先將根節(jié)點(diǎn)入棧,也就是圖中的A節(jié)點(diǎn),然后開(kāi)始遍歷,先將根節(jié)點(diǎn)A出棧,同時(shí)訪問(wèn)根節(jié)點(diǎn)A,并且將其孩子節(jié)點(diǎn)入棧(注意此時(shí)的入棧順序是從最右邊的孩子開(kāi)始往左遍歷,也就是說(shuō)越在左邊的孩子應(yīng)該越早訪問(wèn)到)。后面仿照根節(jié)點(diǎn)A出棧的同時(shí)訪問(wèn),并且將其孩子節(jié)點(diǎn)入棧,代碼如下所示:

public void depthLjFirst(){
        Stack<LjXMLNode> depthStack = new Stack();
        LjXMLNode head = mFinalNodes.get(0);
        depthStack.push(head);
        while ( depthStack.size()> 0 ){
            LjXMLNode cur = depthStack.pop();
            visit(cur);
            for( int i = cur.children.size(); i > 0;i-- ){
                int childId = cur.children.get(i-1);
                depthStack.push( mFinalNodes.get(childId) );
            }
        }
    }

最后完整的代碼如下所示:

package com.lifestudy.stdy.lifestudy.readxml;

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.HashMap;
import java.util.Iterator;
import java.util.Map;
import java.util.Set;
import java.util.Stack;

/**
 * Created by lj on 2017/6/16.
 */

public class LjXMLParser {
    private Stack<LjXMLNode> mStack = new Stack();
    Map<Integer,LjXMLNode> mFinalNodes = new HashMap();
    private int ID_0 = 0;
    public void readXMLFile(InputStream in1){
        try {
            InputStreamReader inputStreamReader = new InputStreamReader(in1);
            BufferedReader in = new BufferedReader(inputStreamReader);
            System.out.println("開(kāi)始輸入:");
            StringBuffer sb = new StringBuffer();
            String s;
            String rest = "";
            while( ( s = in.readLine() ) != null ){
                s = s.trim();
                s = rest + s;

                int start = 0;
                for( int i = 0; i < s.length(); i++ ){
                    if( s.charAt(i) == '>'){
                        process(s.substring(start,i+1));
                        start = i + 1;
                    }
                }
                if( start >= s.length() ){//說(shuō)明處理到最後一個(gè)字符了
                    //do nothing
                }else{
                    rest = s.substring(start,s.length());
                }
            }
//            System.out.println( sb.toString() );
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    /**
     * 處理
     * 主要是對(duì)stack的操作
     */
    private void process(String s){

        String nodeName = "";
        String text = "";

        for( int i = 0; i < s.length();i++ ){
            if( s.charAt(i) == '<'){

                text = s.substring(0,i);
                if( mStack.size() > 0){
                    LjXMLNode topNode = mStack.peek();
                    topNode.text = text;
                }

                if( s.charAt(i+1) != '/'){

                    nodeName = findNodeName(s.substring(i+1));
                    //push
                    LjXMLNode node = new LjXMLNode();
                    node.id = ID_0++;
                    node.name = nodeName;
                    if( mStack.size() > 0){
                        LjXMLNode parentNode = mStack.peek();
                        node.parent = parentNode.id;
                        parentNode.children.add(node.id);
                    }
                    mStack.push(node);

                    for( int j = i+1; j < s.length();j++ ){
                        if( s.charAt(j) == '='){//key:value
                            String key = findFirstLeftWord(s,j);
                            String value = findFirstRightWord(s,j);
                            if( key != ""){
                                LjXMLNode curNode = mStack.peek();
                                curNode.mapKeyValue.put(key,value);
                            }
                        }
                    }

                    for( int j = i+2; j < s.length();j++ ){
                        if( s.charAt(j) == '/'){
                            LjXMLNode shuchuNode =  mStack.pop();
                            shuchuNode.level = mStack.size() + 1;
                            mFinalNodes.put(shuchuNode.id,shuchuNode);
                            System.out.println("shuchuNode:" + "id:"+shuchuNode.id + " name:"+shuchuNode.name
                                    + " key_count:"+shuchuNode.mapKeyValue.size()
                                    + " text:" + shuchuNode.text
                                    +"  parent:"+ shuchuNode.parent);
                        }
                    }

                }else {
                    //pop
                    LjXMLNode shuchuNode =  mStack.pop();
                    shuchuNode.level = mStack.size() + 1;
                    mFinalNodes.put(shuchuNode.id,shuchuNode);
                    System.out.println("shuchuNode:" + "id:"+shuchuNode.id + " name:"+shuchuNode.name
                            + " key_count:"+shuchuNode.mapKeyValue.size()
                            + " text:" + shuchuNode.text
                            +"  parent:"+ shuchuNode.parent);
                }
                break;
            }
        }
    }

    /**
     * 找到右邊的第一個(gè)單詞,只能以空格或者是右括號(hào)“>”結(jié)尾
     */
    private String findNodeName(String s){
        int start,end;
        end = -1;
        start = -1;
        for( int i = 0; i < s.length(); i++){
            if( s.charAt(i) != ' '){ //找到左邊的第一個(gè)字母
                start = i;
//                System.out.println("nodeName_start:" + start);
                break;
            }
        }
        if( start < s.length() && start >= 0){
            for( int i = start + 1; i < s.length(); i++ ){
                if( s.charAt(i) == ' ' || s.charAt(i) == '>'){
                    end = i;
                    break;
                }
            }
        }

        if( start <= end && start != -1){
            return s.substring(start,end);
        }
        return "";
    }

    /**
     * 找到下標(biāo)為loc左邊第一個(gè)單詞
     */
    private String findFirstLeftWord(String s,int loc){
//        System.out.println("開(kāi)始解析:" + s + "###loc:" + loc);
        String key= "";
        int start,end;
        end = -1;
        start = -1;
        for( int i = loc-1; i > 0; i--){
            if( s.charAt(i) != ' '){ //找到左邊的第一個(gè)字母
                end = i;
//                System.out.println("end:" + end);
                break;
            }
        }
//        System.out.println("end解析完成");
        if( end < loc && end > 0){
            for( int i = end; i > 0; i--){
                if( s.charAt(i) == ' '){ //找到左邊的第一個(gè)空格
                    start = i+1;
//                    System.out.println("start:" + start);
                    break;
                }
            }
        }
        if( start <= end && start != -1){
            return s.substring(start,end+1);
        }
        return "";
    }

    /**
     * 找到loc右邊第一個(gè)雙引號(hào)包括的單詞
     */
    private String findFirstRightWord(String s,int loc){
//        System.out.println("s:" + s);
        String value= "";
        int start,end;
        end = -1;
        start = -1;
        for( int i = loc + 1; i < s.length(); i++){
            if( s.charAt(i) == '"'){ //找到右邊的第一個(gè)雙引號(hào)
                start = i;
//                System.out.println("start:" + start);
                break;
            }
        }
        if( start > loc && start < s.length()){
            for( int i = start+1; i < s.length(); i++){
                if( s.charAt(i) == '"'){ //找到右邊的第一個(gè)雙引號(hào)
                    end = i+1;
//                    System.out.println("end:" + end);
                    break;
                }
            }
        }
        if( start <= end && start != -1){
            return s.substring(start,end);
        }
        return "";
    }

    public void depthLjFirst(){
        Stack<LjXMLNode> depthStack = new Stack();
        LjXMLNode head = mFinalNodes.get(0);
        depthStack.push(head);
        while ( depthStack.size()> 0 ){
            LjXMLNode cur = depthStack.pop();
            visit(cur);
            for( int i = cur.children.size(); i > 0;i-- ){
                int childId = cur.children.get(i-1);
                depthStack.push( mFinalNodes.get(childId) );
            }
        }
    }

    private void visit(LjXMLNode node){
        StringBuffer sb = new StringBuffer();
        for( int i = 0; i < node.level; i++){
            sb.append("  ");//三個(gè)空格
        }
        sb.append("" + node.level);
        sb.append("  "+ node.name);
        Set<Map.Entry<String, String>> set2=node.mapKeyValue.entrySet();
        for (Iterator<Map.Entry<String, String>> iterator = set2.iterator(); iterator.hasNext();) {
            Map.Entry<String, String> entry = (Map.Entry<String, String>) iterator.next();
            String key=entry.getKey();
            String valueString=entry.getValue();
            sb.append("  "+ key + "=" + valueString );
        }
        // TODO: 2017/6/16 此處用“!=”來(lái)判斷text是否為空會(huì)出錯(cuò) (why?)
        if( node.text != null&& !node.text.equals("")  ){
            sb.append("  text:" + node.text);
        }

        System.out.println( sb.toString());
    }
}

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