Java8 CopyOnWriteArrayList 源碼解析

前言

一看這個,咋這么長的名字,記起來有點麻煩呀!這個類使用的情況不多,最近在看EventBus的時候看到過,所以還是跳出來學(xué)習(xí)一下,看一下這個類的廬山真面目

是什么東西?

CopyOnWrite,大概能猜到跟寫時復(fù)制有關(guān),為什么要有這個東西?不難想出這是為了線程安全而設(shè)計的,否則直接用 ArrayList 就行了,那好了,說的這個東西就是一個ArrayList ,在此基礎(chǔ)上,他是線程安全的,采用了寫時復(fù)制的方法,那我們可以思考一下,他是怎么做的,如果給我們設(shè)計,我們要怎么做呢?

前世今生

它沒有擴展 ArrayList,即使是以此結(jié)尾,直接實現(xiàn)了 List,也實現(xiàn)了RandomAccess,Cloneable, Serializable 接口,Doug Lea 寫的,就是厲害

public class CopyOnWriteArrayList<E>
    implements List<E>, RandomAccess, Cloneable, java.io.Serializable 

源碼解析

屬性

  • 我們看到了一個鎖,聰明的你可能想到了,是不是可以加鎖來實現(xiàn)線程的安全?在寫的時候加鎖,讀的時候可以不用鎖
  • 同樣使用了 Volatile 的 Object 數(shù)組存儲元素
  • 兩個final 方法設(shè)置 elements
    /**
     * The lock protecting all mutators.  (We have a mild preference
     * for builtin monitors over ReentrantLock when either will do.)
     */
    final transient Object lock = new Object();

    /** The array, accessed only via getArray/setArray. */
    // Android-changed: renamed array -> elements for backwards compatibility b/33916927
    private transient volatile Object[] elements;

    /**
     * Gets the array.  Non-private so as to also be accessible
     * from CopyOnWriteArraySet class.
     */
    final Object[] getArray() {
        return elements;
    }

    /**
     * Sets the array.
     */
    final void setArray(Object[] a) {
        elements = a;
    }

構(gòu)造函數(shù),默認大小為0,也可以傳入集合類對象進行復(fù)制,或者直接傳入數(shù)組,這里用到了 Arrays.copyOf,這是一個數(shù)組復(fù)制的靜態(tài)函數(shù),底層使用了System.arraycopy,效率很高,反悔了一個新的數(shù)組

    /**
     * Creates an empty list.
     */
    public CopyOnWriteArrayList() {
        setArray(new Object[0]);
    }

    /**
     * Creates a list containing the elements of the specified
     * collection, in the order they are returned by the collection's
     * iterator.
     *
     * @param c the collection of initially held elements
     * @throws NullPointerException if the specified collection is null
     */
    public CopyOnWriteArrayList(Collection<? extends E> c) {
        Object[] elements;
        if (c.getClass() == CopyOnWriteArrayList.class)
            elements = ((CopyOnWriteArrayList<?>)c).getArray();
        else {
            elements = c.toArray();
            // defend against c.toArray (incorrectly) not returning Object[]
            // (see e.g. https://bugs.openjdk.java.net/browse/JDK-6260652)
            if (elements.getClass() != Object[].class)
                elements = Arrays.copyOf(elements, elements.length, Object[].class);
        }
        setArray(elements);
    }

    /**
     * Creates a list holding a copy of the given array.
     *
     * @param toCopyIn the array (a copy of this array is used as the
     *        internal array)
     * @throws NullPointerException if the specified array is null
     */
    public CopyOnWriteArrayList(E[] toCopyIn) {
        setArray(Arrays.copyOf(toCopyIn, toCopyIn.length, Object[].class));
    }

函數(shù)

get 沒有加鎖,直接返回,由于volatile,能保證讀到最新的值

    private E get(Object[] a, int index) {
        return (E) a[index];
    }

set,果不其然,對添加數(shù)據(jù)使用了加鎖,首先檢查這個位置是否存在對象,如果不存在,那么需要拷貝一個新的數(shù)組,并且添加一個元素,在調(diào)用elements更新屬性;如果存在了,也需要設(shè)置數(shù)組,保證volatile的語義,這里不是很明白,既然都加了鎖,不需要更新數(shù)據(jù)時還要更新數(shù)據(jù)。最后返回 oldValue。
至于為什么,在這里看到有人討論 concurrency-interest,但感覺也沒有數(shù)清楚,不過我看到了,之前的jdk版本使用了 Lock而不是 synchronized ,可見synchronized 的性能以及大大提高

    public E set(int index, E element) {
        synchronized (lock) {
            Object[] elements = getArray();
            E oldValue = get(elements, index);

            if (oldValue != element) {
                int len = elements.length;
                Object[] newElements = Arrays.copyOf(elements, len);
                newElements[index] = element;
                setArray(newElements);
            } else {
                // Not quite a no-op; ensures volatile write semantics
                setArray(elements);
            }
            return oldValue;
        }
    }

add,依然使用鎖,同樣先讀數(shù)組,在復(fù)制出一個新的數(shù)組,注意,數(shù)組長度為 len + 1,預(yù)留了一個位置,因此這個數(shù)據(jù)結(jié)構(gòu)并沒有類似 *2 的擴容機制,而是一個一個添加,個人覺得這樣效率會大打折扣,當(dāng)然,為了 tradeoff。在添加元素,最后返回true

    public boolean add(E e) {
        synchronized (lock) {
            Object[] elements = getArray();
            int len = elements.length;
            Object[] newElements = Arrays.copyOf(elements, len + 1);
            newElements[len] = e;
            setArray(newElements);
            return true;
        }
    }

add,在某個位置插入一個元素,首先先檢查index,看是否越界,這里使用了一個小技巧,計算了移動距離,如果為0,即添加到最后,則直接復(fù)制,否則就需要調(diào)用兩次 copy 函數(shù)進行復(fù)制

    public void add(int index, E element) {
        synchronized (lock) {
            Object[] elements = getArray();
            int len = elements.length;
            if (index > len || index < 0)
                throw new IndexOutOfBoundsException(outOfBounds(index, len));
            Object[] newElements;
            int numMoved = len - index;
            if (numMoved == 0)
                newElements = Arrays.copyOf(elements, len + 1);
            else {
                newElements = new Object[len + 1];
                System.arraycopy(elements, 0, newElements, 0, index);
                System.arraycopy(elements, index, newElements, index + 1,
                                 numMoved);
            }
            newElements[index] = element;
            setArray(newElements);
        }
    }

remove 可以刪除某個索引的元素

    public E remove(int index) {
        synchronized (lock) {
            Object[] elements = getArray();
            int len = elements.length;
            E oldValue = get(elements, index);
            int numMoved = len - index - 1;
            if (numMoved == 0)
                setArray(Arrays.copyOf(elements, len - 1));
            else {
                Object[] newElements = new Object[len - 1];
                System.arraycopy(elements, 0, newElements, 0, index);
                System.arraycopy(elements, index + 1, newElements, index,
                                 numMoved);
                setArray(newElements);
            }
            return oldValue;
        }
    }

remove也可以刪除某個對象,不過需要遍歷數(shù)組

    public boolean remove(Object o) {
        Object[] snapshot = getArray();
        int index = indexOf(o, snapshot, 0, snapshot.length);
        return (index < 0) ? false : remove(o, snapshot, index);
    }

    private static int indexOf(Object o, Object[] elements,
                               int index, int fence) {
        if (o == null) {
            for (int i = index; i < fence; i++)
                if (elements[i] == null)
                    return i;
        } else {
            for (int i = index; i < fence; i++)
                if (o.equals(elements[i]))
                    return i;
        }
        return -1;
    }

最后還是調(diào)用這個,也是線程安全的函數(shù),邏輯也很簡單

    private boolean remove(Object o, Object[] snapshot, int index) {
        synchronized (lock) {
            Object[] current = getArray();
            int len = current.length;
            if (snapshot != current) findIndex: {
                int prefix = Math.min(index, len);
                for (int i = 0; i < prefix; i++) {
                    if (current[i] != snapshot[i]
                        && Objects.equals(o, current[i])) {
                        index = i;
                        break findIndex;
                    }
                }
                if (index >= len)
                    return false;
                if (current[index] == o)
                    break findIndex;
                index = indexOf(o, current, index, len);
                if (index < 0)
                    return false;
            }
            Object[] newElements = new Object[len - 1];
            System.arraycopy(current, 0, newElements, 0, index);
            System.arraycopy(current, index + 1,
                             newElements, index,
                             len - index - 1);
            setArray(newElements);
            return true;
        }
    }

removeRange 刪除一定范圍,不用說了,相信他的代碼你早就知道該怎么寫了

    void removeRange(int fromIndex, int toIndex) {
        synchronized (lock) {
           .....
        }
    }

addIfAbsent 如果不存在才添加

    public boolean addIfAbsent(E e) {
        Object[] snapshot = getArray();
        return indexOf(e, snapshot, 0, snapshot.length) >= 0 ? false :
            addIfAbsent(e, snapshot);
    }

    /**
     * A version of addIfAbsent using the strong hint that given
     * recent snapshot does not contain e.
     */
    private boolean addIfAbsent(E e, Object[] snapshot) {
        synchronized (lock) {
            Object[] current = getArray();
            int len = current.length;
            if (snapshot != current) {
                // Optimize for lost race to another addXXX operation
                int common = Math.min(snapshot.length, len);
                for (int i = 0; i < common; i++)
                    if (current[i] != snapshot[i]
                        && Objects.equals(e, current[i]))
                        return false;
                if (indexOf(e, current, common, len) >= 0)
                        return false;
            }
            Object[] newElements = Arrays.copyOf(current, len + 1);
            newElements[len] = e;
            setArray(newElements);
            return true;
        }
    }

類似還有 addAllIfAbsent,寫得還是很不錯的,畢竟是 Doug Lea

    public int addAllAbsent(Collection<? extends E> c) {
        Object[] cs = c.toArray();
        if (cs.length == 0)
            return 0;
        synchronized (lock) {
            Object[] elements = getArray();
            int len = elements.length;
            int added = 0;
            // uniquify and compact elements in cs
            for (int i = 0; i < cs.length; ++i) {
                Object e = cs[i];
                if (indexOf(e, elements, 0, len) < 0 &&
                    indexOf(e, cs, 0, added) < 0)
                    cs[added++] = e;
            }
            if (added > 0) {
                Object[] newElements = Arrays.copyOf(elements, len + added);
                System.arraycopy(cs, 0, newElements, len, added);
                setArray(newElements);
            }
            return added;
        }
    }

小結(jié)

分析別人的源碼的過程本身就是一個學(xué)習(xí)的過程,能從中學(xué)到很多新的東西,并且能夠鞏固以前的知識。

歡迎討論~

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