If you know the index of an item

Suppose you have an array, and you want to remove an item in position i.

One method is to use slice():

const items = ['a', 'b', 'c', 'd', 'e', 'f']
const i = 2
const filteredItems = items.slice(0, i).concat(items.slice(i + 1, items.length))
// ["a", "b", "d", "e", "f"]

If you know the value

In this case, one good option is to use filter(), which offers a more declarativeapproach:

const items = ['a', 'b', 'c', 'd', 'e', 'f']
const valueToRemove = 'c'
const filteredItems = items.filter(item => item !== valueToRemove)
// ["a", "b", "d", "e", "f"]

Removing multiple items

By index

You can just create a function and remove items in series:

const items = ['a', 'b', 'c', 'd', 'e', 'f']
 
const removeItem = (items, i) =>
  items.slice(0, i-1).concat(items.slice(i, items.length))
 
let filteredItems = removeItem(items, 3)
filteredItems = removeItem(filteredItems, 5)
//["a", "b", "c", "d"]

By value

You can search for inclusion inside the callback function:

const items = ['a', 'b', 'c', 'd', 'e', 'f']
const valuesToRemove = ['c', 'd']
const filteredItems = items.filter(item => !valuesToRemove.includes(item))
// ["a", "b", "e", "f"]

Avoid mutating the original array

splice() (not to be confused with slice()) mutates the original array, and should be avoided.