There is an objective test result such as “OOXXOXXOOO”. An ‘O’ means a correct answer of a problem
and an ‘X’ means a wrong answer. The score of each problem of this test is calculated by itself and
its just previous consecutive ‘O’s only when the answer is correct. For example, the score of the 10th
problem is 3 that is obtained by itself and its two previous consecutive ‘O’s.
Therefore, the score of “OOXXOXXOOO” is 10 which is calculated by “1+2+0+0+1+0+0+1+2+3”.
You are to write a program calculating the scores of test results.
Input
Your program is to read from standard input. The input consists of T test cases. The number of test
cases T is given in the first line of the input. Each test case starts with a line containing a string
composed by ‘O’ and ‘X’ and the length of the string is more than 0 and less than 80. There is no spaces
between ‘O’ and ‘X’.
Output
Your program is to write to standard output. Print exactly one line for each test case. The line is to
contain the score of the test case.
Sample Input
5
OOXXOXXOOO
OOXXOOXXOO
OXOXOXOXOXOXOX
OOOOOOOOOO
OOOOXOOOOXOOOOX
Sample Output
10
9
7
55
30
解題思路：在一個只有O和X的序列中，X代表0，連續(xù)的O代表首項為1公差為1的等差數(shù)列，如果被X切斷，那么從首項就變成1，重新開始遞增。求被X分割的所有等差數(shù)列an的和。

#include <stdio.h>
#include<string.h>
#define MAX 80

int main()
{
    /* code */
    int T,num,len; 
    scanf("%d",&T);
    char str[MAX];
    while(T--){
    num=1;
    scanf("%s",str);
    len=strlen(str);
    int sum=0;//定義初始總和為0
    for (int i = 0; i < len; i++)
    {
             /*等差數(shù)列求和*/
        if (str[i]=='O')
        {               

            sum+=num;
            num++;
        }
        else
            num=1;


    }
        printf("%d\n",sum);


    }
    return 0;
}