MySQL學(xué)習(xí)筆記-刪除重復(fù)數(shù)據(jù)只保留一條

有這樣一張表,表數(shù)據(jù)及結(jié)果如下:

可以看出,school_name的字段值有重復(fù)數(shù)據(jù)(Abraham Lincoln High School 和Agoura High School分別出現(xiàn)兩次),那么如何刪除這兩條數(shù)據(jù),從而只讓這兩個數(shù)值出現(xiàn)一次呢?

//刪除重復(fù)記錄,保存Id最小的一條
delete FROM `test` WHERE `school_name` 
in 
(SELECT `school_name`
FROM `test` 
GROUP BY `school_name` 
HAVING COUNT( * ) >1) and school_id 
not in 
(select min(school_id) from test group by school_id having count(* )>1)
//刪除重復(fù)記錄,保存Id最大的一條
delete FROM `test` WHERE `school_name` 
in 
(SELECT `school_name`
FROM `test` 
GROUP BY `school_name` 
HAVING COUNT( * ) >1) and school_id 
not in 
(select max(school_id) from test group by school_id having count(* )>1)

一.單個字段的操作

Select 重復(fù)字段 From 表 Group By 重復(fù)字段 Having Count(*)>1

查看是否有重復(fù)的數(shù)據(jù):

GROUP BY <列名序列>

HAVING <組條件表達式>

查詢出:根據(jù)dname分組,同時滿足having字句中組條件表達式(重復(fù)次數(shù)大于1)的那些組

count(*)與count(1) 其實沒有什么差別,用哪個都可以
count(*) 與 count(列名)的區(qū)別:
count(*)將返回表格中所有存在的行的總數(shù)包括值為null的行,然而count(列名)將返回表格中除去null以外的所有行的總數(shù)(有默認值的列也會被計入)

查詢?nèi)恐貜?fù)的數(shù)據(jù):

Select * From 表 Where 重復(fù)字段 
In 
(Select 重復(fù)字段 From 表 Group By 重復(fù)字段 Having Count(*)>1)

二.刪除全部重復(fù)數(shù)據(jù):

將上面的查詢select改為delete(這樣會出錯的)

DELETE
FROM
    dept
WHERE
    dname IN (
        SELECT
            dname
        FROM
            dept
        GROUP BY
            dname
        HAVING
            count(1) > 1
    )

會出現(xiàn)如下錯誤:[Err] 1093 - You can't specify target table 'dept' for update in FROM clause

原因是:更新這個表的同時又查詢了這個表,查詢這個表的同時又去更新了這個表,可以理解為死鎖。

mysql不支持這種更新查詢同一張表的操作

解決辦法:把要更新的幾列數(shù)據(jù)查詢出來做為一個第三方表,然后篩選更新。

DELETE
FROM
    dept
WHERE
    dname IN (
          SELECT
              t.dname
              FROM
                (
        SELECT
            dname
        FROM
            dept
        GROUP BY
            dname
        HAVING
            count(1) > 1
    ) t
)

三.查詢表中多余重復(fù)數(shù)據(jù)

根據(jù)depno來判斷,除了rowid最小的一個

方法一

SELECT
    *
FROM
    dept
WHERE
    dname IN (
        SELECT
            dname
        FROM
            dept
        GROUP BY
            dname
        HAVING
            COUNT(1) > 1
    )
AND deptno NOT IN (
    SELECT
        MIN(deptno)
    FROM
        dept
    GROUP BY
        dname
    HAVING
        COUNT(1) > 1
)

這種寫法正確,但是查詢的速度太慢,可以試一下方法二

方法二

根據(jù)dname分組,查找出deptno最小的;然后再查找deptno不包含剛才查出來的,這樣就查詢出了所有的重復(fù)數(shù)據(jù)(除了deptno最小的那行)

SELECT *
FROM
    dept
WHERE
    deptno NOT IN (
        SELECT
            dt.minno
        FROM
            (
                SELECT
                    MIN(deptno) AS minno
                FROM
                    dept
                GROUP BY
                    dname
            ) dt
    )

第三種方法

SELECT
    * 
FROM
    table_name AS ta 
WHERE
    ta.唯一鍵 <> ( SELECT max( tb.唯一鍵 ) FROM table_name AS tb WHERE ta.判斷重復(fù)的列 = tb.判斷重復(fù)的列 );


四.刪除重復(fù)數(shù)據(jù)只保留一條

第一種方法:

DELETE
FROM
    dept
WHERE
    dname IN (
        SELECT
            t.dname
        FROM
            (
                SELECT
                    dname
                FROM
                    dept
                GROUP BY
                    dname
                HAVING
                    count(1) > 1
            ) t
    )
AND deptno NOT IN (
SELECT
    dt.mindeptno
FROM
    (
        SELECT
            min(deptno) AS mindeptno
        FROM
            dept
        GROUP BY
            dname
        HAVING
            count(1) > 1
    ) dt
)

第二種方法

與上面查詢的第二種方法對應(yīng),只是將select改為delete

DELETE
FROM
    dept
WHERE
    deptno NOT IN (
        SELECT
            dt.minno
        FROM
            (
                SELECT
                    MIN(deptno) AS minno
                FROM
                    dept
                GROUP BY
                    dname
            ) dt
    )

第三種方法

DELETE 
FROM
    table_name AS ta 
WHERE
    ta.唯一鍵 <> (
SELECT
    t.maxid 
FROM
( 
SELECT max( tb.唯一鍵 ) AS maxid FROM table_name AS tb WHERE ta.判斷重復(fù)的列 = tb.判斷重復(fù)的列 )
 t )

五.多個字段的操作(補充)

和單個字段相比,多個字段就是將group by 的字段增加為你想要的即可

DELETE
FROM
    dept
WHERE
    (dname, db_source) IN (
        SELECT
            t.dname,
            t.db_source
        FROM
            (
                SELECT
                    dname,
                    db_source
                FROM
                    dept
                GROUP BY
                    dname,
                    db_source
                HAVING
                    count(1) > 1
            ) t
    )
AND deptno NOT IN (
    SELECT
        dt.mindeptno
    FROM
        (
            SELECT
                min(deptno) AS mindeptno
            FROM
                dept
            GROUP BY
                dname,
                db_source
            HAVING
                count(1) > 1
        ) dt
)

六.小結(jié)

上面的方法還有很多需要優(yōu)化的地方,數(shù)據(jù)量太大的話,執(zhí)行起來很慢

簡單優(yōu)化:

  • 在經(jīng)常查詢的字段上加上索引
  • 將*改為你需要查詢出來的字段,不要全部查詢出來
  • 小表驅(qū)動大表用IN,大表驅(qū)動小表用EXISTS。

IN適合的情況是外表數(shù)據(jù)量小的情況,而不是外表數(shù)據(jù)大的情況.
因為IN會遍歷外表的全部數(shù)據(jù),假設(shè)a表100條,b表10000條那么遍歷次數(shù)就是100*10000次,而exists則是執(zhí)行100次去判斷a表中的數(shù)據(jù)是否在b表中存在,它只執(zhí)行了a.length次數(shù)。
至于哪一個效率高是要看情況的,因為in是在內(nèi)存中比較的,而exists則是進行數(shù)據(jù)庫查詢操作的。

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