Leetcode - Integer to English Words

My code:

public class Solution {
    private final String[] lessThan20 = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
    private final String[] tens = {"", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
    private final String[] thousands = {"", "Thousand", "Million", "Billion"};

    public String numberToWords(int num) {
        if (num == 0) {
            return "Zero";
        }
        String result = "";
        int i = 0;
        while (num > 0) {
            if (num % 1000 != 0) {
                result = helper(num % 1000) + thousands[i] + " " + result;    
            }
            num /= 1000;
            i++;
        }
        return result.trim();
    }

    private String helper(int num) {
        if (num == 0) {
            return "";
        } else if (num < 20) {
            return lessThan20[num] + " ";
        } else if (num < 100) {
            return tens[num / 10] + " " + helper(num % 10);
        } else {
            return lessThan20[num / 100] + " Hundred " + helper(num % 100);
        }
    }
}

時間問題,直接看的答案。這種問題沒必要糾結(jié)。
答案寫的很簡潔。
http://blog.welkinlan.com/2015/09/29/integer-to-english-words-leetcode-java/

Anyway, Good luck, Richardo!

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