
解:原方程可變?yōu)椋?br>
x2=6x+5+√2(x-3)=0.
(x-1)(x-5)+√2(x-3)=0.令x-3=t.
(t+2)(t-2)+√2t=0, t2+√2t=4.
(t+?√2)2=9/2. t+?√2=±?3√2.
t=±?3√2-?√2. t?=√2; t?=-2√2.
x=t+3, x?=3+√2; x?=3-2√2.
百度老師尋求簡(jiǎn)單解法,本人作了解答。百度老師用求根公式解答,計(jì)算太麻煩了!本人巧用換元法計(jì)算,簡(jiǎn)單多了。
解:原方程可變?yōu)椋?br>
x2=6x+5+√2(x-3)=0.
(x-1)(x-5)+√2(x-3)=0.令x-3=t.
(t+2)(t-2)+√2t=0, t2+√2t=4.
(t+?√2)2=9/2. t+?√2=±?3√2.
t=±?3√2-?√2. t?=√2; t?=-2√2.
x=t+3, x?=3+√2; x?=3-2√2.
百度老師尋求簡(jiǎn)單解法,本人作了解答。百度老師用求根公式解答,計(jì)算太麻煩了!本人巧用換元法計(jì)算,簡(jiǎn)單多了。