Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.

The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]" are not.

• 題目大意
  判斷一個包含括號的字符串是否匹配，包括3種括號（'('，'[','{'）

維護一個棧，遇到左括號就壓入棧，遇到右括號就把棧頂?shù)膹棾隹词欠衿ヅ洹?br> 注意最后要檢查棧是否為空。

/**
 * @param {string} s
 * @return {boolean}
 */
const isValid = function (s) {
  const stack = [];
  const leftSet = new Set(['(', '[', '{']);
  const rightSet = new Set([')', ']', '}']);
  const pair = {
    ')': '(',
    ']': '[',
    '}': '{',
  };
  for (let i = 0; i < s.length; i++) {
    const char = s[i];
    if (leftSet.has(char)) {
      stack.push(char);
    }
    if (rightSet.has(char)) {
      if (stack.pop() !== pair[char]) {
        return false;
      }
    }
  }
  return stack.length === 0;
};