描述

給你一個(gè)整數(shù)n. 從 1 到 n 按照下面的規(guī)則打印每個(gè)數(shù)：
如果這個(gè)數(shù)被3整除，打印fizz.
如果這個(gè)數(shù)被5整除，打印buzz.
如果這個(gè)數(shù)能同時(shí)被3和5整除，打印fizz buzz.

樣例

比如 n = 15, 返回一個(gè)字符串?dāng)?shù)組：

[
  "1", "2", "fizz",
  "4", "buzz", "fizz",
  "7", "8", "fizz",
  "buzz", "11", "fizz",
  "13", "14", "fizz buzz"
]

挑戰(zhàn)

Can you do it with only one if statement?

代碼

public class Solution {
    /*
     * @param n: An integer
     * @return: A list of strings.
     */
    public List<String> fizzBuzz(int n) {
        // write your code here
        ArrayList<String> results = new ArrayList<String>();
        // 從 1 到 n
        for (int i = 1; i <= n; i++) {
            if (i % 15 == 0) {
                results.add("fizz buzz");
            } else if (i % 5 == 0) {
                results.add("buzz");
            } else if (i % 3 == 0) {
                results.add("fizz");
            } else {
                results.add(String.valueOf(i));
            }
        }
        return results;
    }
}