66. Plus One

Problem

Given a non-empty array of digits representing a non-negative integer, plus one to the integer.

The digits are stored such that the most significant digit is at the head of the list, and each element in the array contain a single digit.

You may assume the integer does not contain any leading zero, except the number 0 itself.

Example

Input: [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.
Input: [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.

Code

static int var = [](){
    std::ios::sync_with_stdio(false);
    cin.tie(NULL);
    return 0;
}();
class Solution {
public:
    vector<int> plusOne(vector<int>& digits) {
        int i = digits.size()-1;
        digits[i] += 1;
        while(digits[i]==10 && i>0){
            digits[i] = 0;
            digits[i-1] += 1;
            i--;
        }
        if(digits[0]==10){
            digits[0] = 0;
            digits.insert(digits.begin(),1);
        }
        return digits;
    }
};

Result

66. Plus One.png
?著作權(quán)歸作者所有,轉(zhuǎn)載或內(nèi)容合作請聯(lián)系作者
【社區(qū)內(nèi)容提示】社區(qū)部分內(nèi)容疑似由AI輔助生成,瀏覽時請結(jié)合常識與多方信息審慎甄別。
平臺聲明:文章內(nèi)容(如有圖片或視頻亦包括在內(nèi))由作者上傳并發(fā)布,文章內(nèi)容僅代表作者本人觀點,簡書系信息發(fā)布平臺,僅提供信息存儲服務(wù)。

相關(guān)閱讀更多精彩內(nèi)容

友情鏈接更多精彩內(nèi)容