最近在把Python的定時程序放進Windows服務(wù)時遇到了上述的問題‘錯誤1053：服務(wù)沒有及時響應(yīng)啟動或控制請求’ 或者 ‘Error 1053: The service did not respond to the start or control request in a timely fashion’。
可以正常安裝python PythonFileName.py install，
不能正常啟動python PythonFileName.py start。
嘗試使用python PythonFileName.py debug檢查代碼，沒有發(fā)現(xiàn)代碼問題，考慮應(yīng)該是環(huán)境問題。

最終在StackOverflow的 Can't start Windows service written in Python (win32serviceutil) 中找到了 BuvinJ 的回答：“It might prove useful in this case to also add these directories to your system path: C:\Python27\Lib\site-packages\win32 and C:\Python27\Lib\site-packages\pywin32_system32. That will let you use pythonservice more easily. ”

解決辦法

在cmd中輸入
setx /M PATH "%PATH%;C:\Python27;C:\Users\Administrator\Anaconda2\Scripts;C:\Users\Administrator\Anaconda2\Lib\site-packages\pywin32_system32;C:\Users\Administrator\Anaconda2\Lib\site-packages\win32"
回車，增加兩個路徑的引用。然后就能啟動服務(wù)了。

具體的Windows服務(wù)Python代碼：

import sys
import win32serviceutil
import win32service
import win32event
import servicemanager
import winerror

class StockRecommendRunLoop(win32serviceutil.ServiceFramework):
    _svc_name_ = "StockRecommendRunLoop"
    _svc_display_name_ = "Stock Recommend Run Loop"

    def __init__(self, args):
        win32serviceutil.ServiceFramework.__init__(self, args)
        self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)

    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        win32event.SetEvent(self.hWaitStop)

    def SvcDoRun(self):
        self.ReportServiceStatus(win32service.SERVICE_RUNNING)
        self.start_task()
        win32event.WaitForSingleObject(self.hWaitStop, win32event.INFINITE)

if __name__ == '__main__':
    if len(sys.argv) == 1:
        try:
            servicemanager.Initialize()
            servicemanager.PrepareToHostSingle(StockRecommendRunLoop)
            servicemanager.StartServiceCtrlDispatcher()
        except win32service.error, details:
            if details[0] == winerror.ERROR_FAILED_SERVICE_CONTROLLER_CONNECT:
                win32serviceutil.usage()
    else:
        win32serviceutil.HandleCommandLine(StockRecommendRunLoop)

Reference:

Can't start Windows service written in Python (win32serviceutil)
Python Windows Service的方式運行