This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.
Sample Input
1 1
8600 8600
Sample Output
no
yes

問題鏈接(https://vjudge.net/problem/HDU-2101)

問題簡述：輸入A,B值，對A+B的結(jié)果進行判斷。如果(A+B)%86=0，則輸出yes，否則就輸出no。

問題分析：這是簡單的一道對If語句的一個考查。本程序運用if語句對輸入的A B值直接進行判斷。

AC通過的C++語言如下

#include<iostream>
using namespace std;
int main()
{
    int A, B;
    while (cin >> A >> B)
    {
        if ((A + B) % 86 == 0)
        {
            cout << "yes" << endl;
        }
        else cout << "no" << endl;
    }
    return 0;
}