題目

Given an array and a value, remove all instances of that value in place and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

Example:
Given input array nums = [3,2,2,3], val = 3

Your function should return length = 2, with the first two elements of nums being 2.

解題思路

題目要求把數(shù)組中等于val的值都去掉，然后返回新數(shù)組的長度
用i遍歷數(shù)組，len2為新數(shù)組的索引，只記錄不等于val的值

代碼

func removeElement(nums []int, val int) int {
    len1 := len(nums)
    var len2 int
    for i := 0; i < len1; i++{
        if val != nums[i] {
            if len2 < i {
                nums[len2] = nums[i]
            }
            len2++
        }
    }
    nums = nums[:len2]
    return len2
}