Leetcode 997. Find the Town Judge

文章作者:Tyan
博客:noahsnail.com ?|? CSDN ?|? 簡書

1. Description

Find the Town Judge

2. Solution

  • Version 1
class Solution:
    def findJudge(self, N, trust):
        if N == 1:
            return 1
        if len(trust) < N - 1:
            return -1
        judge = {}
        people = {}
        for pair in trust:
            people[pair[0]] = people.get(pair[0], 0) + 1
            judge[pair[1]] = judge.get(pair[1], 0) + 1

        for key, value in judge.items():
            if value == N - 1 and key not in people:
                return key

        return -1
  • Version 2
class Solution:
    def findJudge(self, N, trust):
        count = [0] * (N + 1)
        for pair in trust:
            count[pair[0]] -= 1
            count[pair[1]] += 1
        
        for i in range(1, len(count)):
            if count[i] == N - 1:
                return i
        return -1

Reference

  1. https://leetcode.com/problems/find-the-town-judge/submissions/
?著作權(quán)歸作者所有,轉(zhuǎn)載或內(nèi)容合作請聯(lián)系作者
【社區(qū)內(nèi)容提示】社區(qū)部分內(nèi)容疑似由AI輔助生成,瀏覽時請結(jié)合常識與多方信息審慎甄別。
平臺聲明:文章內(nèi)容(如有圖片或視頻亦包括在內(nèi))由作者上傳并發(fā)布,文章內(nèi)容僅代表作者本人觀點,簡書系信息發(fā)布平臺,僅提供信息存儲服務(wù)。

相關(guān)閱讀更多精彩內(nèi)容

友情鏈接更多精彩內(nèi)容