問題：線程池中的線程執(zhí)行任務(wù)出現(xiàn)異常，該線程接下來的命運(yùn)如何？

結(jié)論：線程會結(jié)束，線程池會新建線程替換該線程

驗(yàn)證：編碼驗(yàn)證，代碼如下

public class ThreadPoolExceptionTest {

    // 創(chuàng)建一個(gè)核心線程數(shù)、最大線程數(shù)都為1的線程池，任務(wù)隊(duì)列最大容量為10
    private static ThreadPoolExecutor executor = new ThreadPoolExecutor(1, 1,
            0L, TimeUnit.SECONDS,
            new ArrayBlockingQueue<>(10),
            new java.util.concurrent.ThreadPoolExecutor.DiscardPolicy());

    public static void main(String[] args) {

        executor.execute(() -> System.out.println(Thread.currentThread().getName() + " " + (1 / 0)));
        try {
            // 睡眠1秒，讓打印結(jié)果更明顯
            Thread.sleep(1000L);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }

        executor.execute(() -> System.out.println(Thread.currentThread().getName() + " " + (1 / 1)));
        executor.execute(() -> System.out.println(Thread.currentThread().getName() + " " + (1 / 2)));
        executor.execute(() -> System.out.println(Thread.currentThread().getName() + " " + (1 / 3)));
        executor.execute(() -> System.out.println(Thread.currentThread().getName() + " " + (1 / 4)));

    }
}

• 打印日志如下：

Exception in thread "pool-1-thread-1" java.lang.ArithmeticException: / by zero
    at com.lushwe.thread.ThreadPoolExceptionTest.lambda$main$0(ThreadPoolExceptionTest.java:25)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1149)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:624)
    at java.lang.Thread.run(Thread.java:748)
pool-1-thread-2 1
pool-1-thread-2 0
pool-1-thread-2 0
pool-1-thread-2 0

• 總結(jié)：通過日志線程的線程名稱可知，線程執(zhí)行任務(wù)出現(xiàn)異常，該線程會結(jié)束，線程池會創(chuàng)建新的線程替換該線程執(zhí)行其他任務(wù)。

本文完。