1. iOS 9.0之前獲取通訊錄的方法

- (void)fetchAddressBookBeforeIOS9{
    ABAddressBookRef addressBook = ABAddressBookCreate();
    //首次訪問需用戶授權
    if (ABAddressBookGetAuthorizationStatus() == kABAuthorizationStatusNotDetermined) {//首次訪問通訊錄
        ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
            if (!error) {
                if (granted) {//允許
                    NSLog(@"已授權訪問通訊錄");
                    NSArray *contacts = [self fetchContactWithAddressBook:addressBook];
                    dispatch_async(dispatch_get_main_queue(), ^{
                        //----------------主線程 更新 UI-----------------
                        NSLog(@"contacts:%@", contacts);
                        
                        
                        
                    });
                }else{//拒絕
                    NSLog(@"拒絕訪問通訊錄");
                }
            }else{
                NSLog(@"發(fā)生錯誤!");
            }
        });
    }else{//非首次訪問通訊錄
        NSArray *contacts = [self fetchContactWithAddressBook:addressBook];
        dispatch_async(dispatch_get_main_queue(), ^{
            //----------------主線程 更新 UI-----------------
            NSLog(@"contacts:%@", contacts);
            
            
            
        });
    }
}

- (NSMutableArray *)fetchContactWithAddressBook:(ABAddressBookRef)addressBook{
    if (ABAddressBookGetAuthorizationStatus() == kABAuthorizationStatusAuthorized) {////有權限訪問
        //獲取聯(lián)系人數(shù)組
        NSArray *array = (__bridge NSArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);
        NSMutableArray *contacts = [NSMutableArray array];
        for (int i = 0; i < array.count; i++) {
            //獲取聯(lián)系人
            ABRecordRef people = CFArrayGetValueAtIndex((__bridge ABRecordRef)array, i);
            //獲取聯(lián)系人詳細信息,如:姓名,電話,住址等信息
            NSString *firstName = (__bridge NSString *)ABRecordCopyValue(people, kABPersonFirstNameProperty);
            NSString *lastName = (__bridge NSString *)ABRecordCopyValue(people, kABPersonLastNameProperty);
            ABMutableMultiValueRef *phoneNumRef = ABRecordCopyValue(people, kABPersonPhoneProperty);
            NSString *phoneNumber =  ((__bridge NSArray *)ABMultiValueCopyArrayOfAllValues(phoneNumRef)).lastObject;
            [contacts addObject:@{@"name": [firstName stringByAppendingString:lastName], @"phoneNumber": phoneNumber}];
        }
        return contacts;
    }else{//無權限訪問
        NSLog(@"無權限訪問通訊錄");
        return nil;
    }
}

打印結果:

iOS 9.0之前

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2. iOS 9.0 及 iOS 9.0之后獲取通訊錄的方法

- (void)fetchAddressBookOnIOS9AndLater{
    //創(chuàng)建CNContactStore對象
    CNContactStore *contactStore = [[CNContactStore alloc] init];
    //首次訪問需用戶授權
    if ([CNContactStore authorizationStatusForEntityType:CNEntityTypeContacts] == CNAuthorizationStatusNotDetermined) {//首次訪問通訊錄
        [contactStore requestAccessForEntityType:CNEntityTypeContacts completionHandler:^(BOOL granted, NSError * _Nullable error) {
            if (!error){
                if (granted) {//允許
                    NSLog(@"已授權訪問通訊錄");
                    NSArray *contacts = [self fetchContactWithContactStore:contactStore];//訪問通訊錄
                    dispatch_async(dispatch_get_main_queue(), ^{
                        //----------------主線程 更新 UI-----------------
                        NSLog(@"contacts:%@", contacts);
                        
                        
                        
                    });
                }else{//拒絕
                    NSLog(@"拒絕訪問通訊錄");
                }
            }else{
                NSLog(@"發(fā)生錯誤!");
            }
        }];
    }else{//非首次訪問通訊錄
        NSArray *contacts = [self fetchContactWithContactStore:contactStore];//訪問通訊錄
        dispatch_async(dispatch_get_main_queue(), ^{
            //----------------主線程 更新 UI-----------------
            NSLog(@"contacts:%@", contacts);
            
            
            
        });
    }
}

- (NSMutableArray *)fetchContactWithContactStore:(CNContactStore *)contactStore{
    //判斷訪問權限
    if ([CNContactStore authorizationStatusForEntityType:CNEntityTypeContacts] == CNAuthorizationStatusAuthorized) {//有權限訪問
        NSError *error = nil;
        //創(chuàng)建數(shù)組,必須遵守CNKeyDescriptor協(xié)議,放入相應的字符串常量來獲取對應的聯(lián)系人信息
        NSArray <id<CNKeyDescriptor>> *keysToFetch = @[CNContactFamilyNameKey, CNContactGivenNameKey, CNContactPhoneNumbersKey];
        //獲取通訊錄數(shù)組
        NSArray<CNContact*> *arr = [contactStore unifiedContactsMatchingPredicate:nil keysToFetch:keysToFetch error:&error];
        if (!error) {
            NSMutableArray *contacts = [NSMutableArray array];
            for (int i = 0; i < arr.count; i++) {
                CNContact *contact = arr[i];
                NSString *givenName = contact.givenName;
                NSString *familyName = contact.familyName;
                NSString *phoneNumber = ((CNPhoneNumber *)(contact.phoneNumbers.lastObject.value)).stringValue;
                [contacts addObject:@{@"name": [givenName stringByAppendingString:familyName], @"phoneNumber": phoneNumber}];
            }
            return contacts;
        }else {
            return nil;
        }
    }else{//無權限訪問
        NSLog(@"無權限訪問通訊錄");
        return nil;
    }
}

打印結果:

iOS 9.0 及之后

</br>
PS:這里沒有做排序, 需要自己做排序處理.