項(xiàng)目有這個(gè)需求,網(wǎng)上找了很多,大部分表情都能限制,但是總有一些漏網(wǎng)之魚,類似 ??這個(gè).最后在github上找到了一個(gè)2016年作者寫的,竟然能全部屏蔽掉,鏈接,這個(gè)里面好幾個(gè)方法,我使用到的是判斷字符串是否為emoji

注意:方法和百度來的很類似,但里面實(shí)際有一些不一樣的,可以試一下

+ (BOOL)stringContainsEmoji:(NSString *)string
{
    // 過濾所有表情。returnValue為NO表示不含有表情，YES表示含有表情
    __block BOOL containsEmoji = NO;
    [string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
        
        const unichar hs = [substring characterAtIndex:0];
        // surrogate pair
        
        if (0xd800 <= hs &&
            hs <= 0xdbff)
        {
            if (substring.length > 1)
            {
                const unichar ls = [substring characterAtIndex:1];
                const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
                if (0x1d000 <= uc &&
                    uc <= 0x1f9c0)
                {
                    containsEmoji = YES;
                }
            }
        }
        else if (substring.length > 1)
        {
            const unichar ls = [substring characterAtIndex:1];
            if (ls == 0x20e3 ||
                ls == 0xfe0f ||
                ls == 0xd83c)
            {
                containsEmoji = YES;
            }
        }
        else
        {
            // non surrogate
            if (0x2100 <= hs &&
                hs <= 0x27ff)
            {
                containsEmoji = YES;
            }
            else if (0x2B05 <= hs &&
                     hs <= 0x2b07)
            {
                containsEmoji = YES;
            }
            else if (0x2934 <= hs &&
                     hs <= 0x2935)
            {
                containsEmoji = YES;
            }
            else if (0x3297 <= hs &&
                     hs <= 0x3299)
            {
                containsEmoji = YES;
            }
            else if (hs == 0xa9 ||
                     hs == 0xae ||
                     hs == 0x303d ||
                     hs == 0x3030 ||
                     hs == 0x2b55 ||
                     hs == 0x2b1c ||
                     hs == 0x2b1b ||
                     hs == 0x2b50)
            {
                containsEmoji = YES;
            }
        }
        
        if (containsEmoji)
        {
            *stop = YES;
        }
    }];
    return containsEmoji;
}

這個(gè)判斷下有個(gè)問題是九宮格輸入法直接是不能輸入內(nèi)容的,所以還需要再判斷一下是否為九宮格輸入法,判斷方法:

+(BOOL)isNineKeyBoard:(NSString *)string
{
    NSString *other = @"????????";
    int len = (int)string.length;
    for(int i=0;i<len;i++)
    {
        if(!([other rangeOfString:string].location != NSNotFound))
            return NO;
    }
    return YES;
}