Remove all elements from a linked list of integers that have value val.

Example
Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
Return:* 1 --> 2 --> 3 --> 4 --> 5

Credits:Special thanks to @mithmatt for adding this problem and creating all test cases.

題意：給一個鏈表，給一個數(shù)字，把鏈表中和這個數(shù)字的結(jié)點(diǎn)值相同的結(jié)點(diǎn)，全部都干掉

思路：自己創(chuàng)建一個頭結(jié)點(diǎn)，用來完成后，還能找到這個鏈表，然后就可以往后遍歷了，當(dāng)發(fā)現(xiàn)遇到同樣的值直接跳過就可以了，最后返回這個頭結(jié)點(diǎn)了。

java代碼：

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
class Solution {
  public ListNode removeElements(ListNode head, int val) {
       
      ListNode first = new ListNode(1);
        first.next = head;

        ListNode temp = first;

        while (temp.next != null) {
            if (temp.next.val == val) {
                temp.next = temp.next.next;
            } else {
                temp = temp.next;
            }
        }
        return first.next;
        
    }
}