//動態(tài)多態(tài)-實現(xiàn)基類和派生類同名函數(shù)問題
#include <iostream>
#include <string>
using namespace std;

class Student{
    public:
        Student(int,string,float);
        virtual void display();
    protected:
        int num;
        string name;
        float score;
};
Student::Student(int n,string nam,float s){
    num = n;name = nam;score = s;
}
void Student::display(){
    cout<<"num:"<<num<<"\nname:"<<name<<"\nscore:"<<score<<"\n\n";
}
class Graduate:public Student{
    public:
        Graduate(int,string,float,float);
        void display();
    private:
        float wage;
};
Graduate::Graduate(int n,string nam,float s,float w):Student(n,nam,s),wage(w){
}
void Graduate::display(){
    cout<<"num:"<<num<<"\nname:"<<name<<"\nscore"<<score<<"\nwage="<<wage<<endl;
}

int main(){
    Student stu1(1000,"rice",87.9);
    Graduate grad1(2001,"Rice",90.0,1200);
    Student *pt = &stu1;
    pt->display();
    pt = &grad1;
    pt->display();    //同一個pt指針，實現(xiàn)對象的多態(tài)性，當然，你也可以用兩個不同得指針實現(xiàn)，但這就不是多態(tài)性了（記住多態(tài)的定義） 
    return 0;
}