作業(yè)一

#include<stdio.h>

int main()
{
 int i, j, k, cnt = 0;
 for (i = 0; i <= 10; i ++)
  for (j = 0; j <= 10; j += 2)
   for (k = 0; k <= 10; k +=5)
    if (i + j + k == 10)
     cnt ++;
 printf("%d\n", cnt);
}

作業(yè)二

#include <stdio.h>

int main ()
{
 int m, n, p, tmp;

 printf ("請輸入兩個整數(shù):\n");
 scanf ("%i %i", &m, &n);        
 p=m*n;                          

 while (n!=0){
  tmp=m%n;
  m=n;
  n=tmp;                  
 }  
 printf ("最大公約數(shù) %i\n", p/m);

 return 0;
}