手擼golang 基本數(shù)據(jù)結(jié)構(gòu)與算法 最大公約數(shù) 歐幾里得算法/輾轉(zhuǎn)相除法

緣起

最近閱讀<<我的第一本算法書>>(【日】石田保輝;宮崎修一)
本系列筆記擬采用golang練習(xí)之

歐幾里得算法

歐幾里得算法(又稱輾轉(zhuǎn)相除法)用于計算兩個數(shù)的最大公約數(shù),
被稱為世界上最古老的算法。
現(xiàn)在人們已無法確定該算法具體的提出時間,
但其最早被發(fā)現(xiàn)記載于公元前300年歐幾里得的著作中,
因此得以命名。

首先用較小的數(shù)字去除較大的數(shù)字,求出余數(shù)。
接下來再用較小的除數(shù)和余數(shù)進行mod運算,
重復(fù)同樣的操作,
余數(shù)為0時,最后一次運算中的除數(shù)就是最大公約數(shù)。

摘自 <<我的第一本算法書>> 【日】石田保輝;宮崎修一
Euclidean-algorithm.jpg

目標

  • 分別用因式分解法和歐幾里德算法求解若干隨機整數(shù)的最大公約數(shù), 并相互驗證

設(shè)計

  • IGCDCalculator: 最大公約數(shù)計算器接口
  • tEuclideanCalculator: 歐幾里德算法實現(xiàn)最大公約數(shù)求解
  • tNormalGcdCalculator: 因式分解法實現(xiàn)最大公約數(shù)求解

單元測試

euclidean_gcd_test.go, 對比驗證歐幾里德算法和因式分解法, 并比較計算效率

package others

import (
    "learning/gooop/others/euclidean"
    "math/rand"
    "testing"
    "time"
)

func TestEuclideanGCD(t *testing.T) {
    fnAssertTrue := func(b bool, msg string) {
        if !b {
            t.Fatal(msg)
        }
    }

    rnd := rand.New(rand.NewSource(time.Now().UnixNano()))
    sampleCount := 100
    samples := make([]int, sampleCount)
    for i,_ := range samples {
        samples[i] = rnd.Intn(sampleCount) + 1
    }

    fnGenInt := func() int {
        n := rnd.Intn(5) + 1
        x := 1
        for i := 0;i < n;i++ {
            j := rnd.Intn(sampleCount)
            x *= samples[j]
        }
        return x
    }

    c1 := euclidean.EuclideanGCDCalculator
    c2 := euclidean.NormalGCDCalculator

    t.Log("testing 10 samples")
    for i := 0;i < 10;i++ {
        a,b := fnGenInt(), fnGenInt()
        g1 := c1.Calc(a, b)
        g2 := c2.Calc(a, b)
        //t.Logf("a=%v, b=%v, g1=%v, g2=%v", a, b, g1, g2)

        fnAssertTrue(g1 == g2, "expecting g1 == g2")
        fnAssertTrue(a % g1 == 0, "expecting a % gcd == 0")
        fnAssertTrue(b % g1 == 0, "expecting b % gcd == 0")
        t.Logf("gcd(%v, %v) = %v", a, b, g1)
    }
    t.Log("pass testing 10 samples")

    t.Log("\ntesting 100_000 samples")
    for i := 0;i < 100_000;i++ {
        a,b := fnGenInt(), fnGenInt()
        g1 := c1.Calc(a, b)
        g2 := c2.Calc(a, b)

        fnAssertTrue(g1 == g2, "expecting g1 == g2")
        fnAssertTrue(a % g1 == 0, "expecting a % gcd == 0")
        fnAssertTrue(b % g1 == 0, "expecting b % gcd == 0")
    }
    t.Log("pass testing 100_000 samples")

    fnTestCost := func(samples[][] int, c euclidean.IGCDCalculator) int64 {
        t0 := time.Now().UnixNano()
        for i, size := 0, len(samples);i < size;i++ {
            a, b := samples[i][0], samples[i][1]
            g1 := c.Calc(a, b)

            fnAssertTrue(a%g1 == 0, "expecting a % gcd == 0")
            fnAssertTrue(b%g1 == 0, "expecting b % gcd == 0")
        }
        cost := (time.Now().UnixNano() - t0) / 1000_000
        return cost
    }

    pairs := make([][]int, 10_000)
    for i,size := 0, len(pairs);i < size;i++ {
        pairs[i] = []int{ fnGenInt(), fnGenInt() }
    }
    t.Logf("testing 10_000 samples using EuclideanGCDCalculator, cost=%v ms", fnTestCost(pairs, c1))
    t.Logf("testing 10_000 samples using NormalGCDCalculator, cost=%v ms", fnTestCost(pairs, c2))
}

測試輸出

顯而易見, 歐幾里德算法要快上N個數(shù)量級

$ go test -v euclidean_gcd_test.go 
=== RUN   TestEuclideanGCD
    euclidean_gcd_test.go:37: testing 10 samples
    euclidean_gcd_test.go:47: gcd(122262, 2135280) = 1722
    euclidean_gcd_test.go:47: gcd(2563600, 180180) = 260
    euclidean_gcd_test.go:47: gcd(5, 2019600) = 5
    euclidean_gcd_test.go:47: gcd(78540, 1547) = 119
    euclidean_gcd_test.go:47: gcd(17476560, 749800800) = 563760
    euclidean_gcd_test.go:47: gcd(395600, 12792) = 8
    euclidean_gcd_test.go:47: gcd(21, 165) = 3
    euclidean_gcd_test.go:47: gcd(7056, 2257) = 1
    euclidean_gcd_test.go:47: gcd(90, 918) = 18
    euclidean_gcd_test.go:47: gcd(90843648, 2522520) = 1176
    euclidean_gcd_test.go:49: pass testing 10 samples
    euclidean_gcd_test.go:51: 
        testing 100_000 samples
    euclidean_gcd_test.go:61: pass testing 100_000 samples
    euclidean_gcd_test.go:80: testing 10_000 samples using EuclideanGCDCalculator, cost=1 ms
    euclidean_gcd_test.go:81: testing 10_000 samples using NormalGCDCalculator, cost=721 ms
--- PASS: TestEuclideanGCD (8.34s)
PASS
ok      command-line-arguments  8.347s

IGCDCalculator.go

最大公約數(shù)計算器接口

package euclidean

type IGCDCalculator interface {
    Calc(a, b int) int
}

tEuclideanCalculator.go

歐幾里德算法實現(xiàn)最大公約數(shù)求解

package euclidean

type tEuclideanCalculator struct {
}

func newEuclideanCalculator() IGCDCalculator {
    return &tEuclideanCalculator{}
}

func (me *tEuclideanCalculator) Calc(a, b int) int {
    if a <= 0 || b <= 0 {
        return 1
    }

    if a == b {
        return a
    }

    bigger := max(a, b)
    smaller := min(a, b)

    for smaller > 0 {
        remaining := bigger % smaller
        if remaining == 0 {
            return smaller
        } else {
            bigger ,smaller = smaller, remaining
        }
    }

    return 1
}

func max(a, b int) int {
    if a >= b {
        return a
    }
    return b
}

func min(a, b int) int {
    if a <= b {
        return a
    }
    return b
}

var EuclideanGCDCalculator = newEuclideanCalculator()

tNormalGcdCalculator.go

因式分解法實現(xiàn)最大公約數(shù)求解

package euclidean

import (
    "math"
    "sort"
)

type tNormalGcdCalculator struct {
}

func newNormalGcdCalculator() IGCDCalculator {
    return &tNormalGcdCalculator{}
}


func (me *tNormalGcdCalculator) Calc(a, b int) int {
    if a <= 0 || b <= 0 {
        return 1
    }

    if a == b {
        return a
    }

    aa := me.split(a)
    sort.Sort(sort.IntSlice(aa))

    bb := me.split(b)
    sort.Sort(sort.IntSlice(bb))

    for i, j := len(aa) - 1, len(bb) - 1;i >= 0 && j >= 0; {
        if aa[i] == bb[j] {
            return aa[i]
        }

        if aa[i] > bb[j] {
            i--
        } else {
            j--
        }
    }

    return 1
}

func (me *tNormalGcdCalculator) split(a int) []int {
    to := int(math.Floor(math.Sqrt(float64(a))))
    items := make([]int, 0)
    for i := 1;i <= to;i++ {
        if a % i == 0 {
            items = append(items, i)
            items = append(items, a / i)
        }
    }
    return items
}

var NormalGCDCalculator = newNormalGcdCalculator()

(end)

?著作權(quán)歸作者所有,轉(zhuǎn)載或內(nèi)容合作請聯(lián)系作者
【社區(qū)內(nèi)容提示】社區(qū)部分內(nèi)容疑似由AI輔助生成,瀏覽時請結(jié)合常識與多方信息審慎甄別。
平臺聲明:文章內(nèi)容(如有圖片或視頻亦包括在內(nèi))由作者上傳并發(fā)布,文章內(nèi)容僅代表作者本人觀點,簡書系信息發(fā)布平臺,僅提供信息存儲服務(wù)。

相關(guān)閱讀更多精彩內(nèi)容

友情鏈接更多精彩內(nèi)容