讀入一個正整數(shù) n，計算其各位數(shù)字之和，用漢語拼音寫出和的每一位數(shù)字。

輸入格式：
每個測試輸入包含 1 個測試用例，即給出自然數(shù) n 的值。這里保證 n 小于 10^100。

輸出格式：
在一行內輸出 n 的各位數(shù)字之和的每一位，拼音數(shù)字間有 1 空格，但一行中最后一個拼音數(shù)字后沒有空格。

輸入樣例：

1234567890987654321123456789

輸出樣例：

yi san wu

C語言：

#include <stdio.h>
int main()
{
    int sum = 0;
    char c;
    char *pinyin[] = {"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
    while ((c = getchar()) != '\n') {
        sum += c - '0';
    }
    if (sum / 100 != 0) {
        printf("%s ", pinyin[sum / 100]);
    }
    if (sum / 10 != 0) {
        printf("%s ", pinyin[sum / 10 % 10]);
    }
    printf("%s", pinyin[sum % 10]);
}

Java語言：

import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        String[] pinyins = {"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
        Scanner sc = new Scanner(System.in);
        String str = sc.nextLine();
        int sum = 0;
        for (int i = 0; i < str.length(); i++) {
            sum += str.charAt(i) - '0';
        }
        if (sum / 100 != 0) {
            System.out.print(pinyins[sum / 100] + " ");
        }
        if (sum / 10 != 0) {
            System.out.print(pinyins[sum / 10 % 10] + " ");
        }
        System.out.print(pinyins[sum % 10]);
    }
}