讀程序，總結(jié)程序的功能

1.

numbers=1
for  x in range(0,20):
    numbers*=2
print(numbers)

功能：求出number的range()次方

2.

summation=0
num=1
while num<=100:
 if (num%3==0 or num%7==0) and num%21!=0:
 summation += 1
 num+=1
print(summation)

功能：在1~100之間找出一個(gè)被21整除后不等于零同時(shí)能被3或者7整除的一個(gè)數(shù)

編程實(shí)現(xiàn)for和while各寫一遍

1. 求1到100之間所有數(shù)的和、平均值

2. 計(jì)算1-100之間能3整除的數(shù)的和

3. 計(jì)算1-100之間不能被7整除的數(shù)的和

1.

number1=0
for x in range(1,101):
    number1+=x
print(number1)

number = 1  
sum1 = 0  
while number <= 100:
    
    sum1 += number

    
    number += 1

print(sum1)

print(number1/100)

print(sum1/100)

mmm=0
for x in range(1,100):
    if x % 3 ==0:
        mmm+=x
print(mmm)

num=0
number=1
while number<=100 :
    if number % 3 ==0:
        num+=number
    num+=1
print(num)

num=0
for x in range(1,100):
    if x% 7 !=0:
        num+=x
print(num)      

num=0
number=1
while number<=100:
    if number %7 !=0:
        num+=number
    num+=1

print(num)