/*
* 68. Text Justification
Total Accepted: 36777
Total Submissions: 220301
Difficulty: Hard
Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified.
You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad extra spaces ' ' when necessary so that each line has exactly L characters.
Extra spaces between words should be distributed as evenly as possible. If the number of spaces on a line do not divide evenly between words, the empty slots on the left will be assigned more spaces than the slots on the right.
For the last line of text, it should be left justified and no extra space is inserted between words.
For example,
words: ["This", "is", "an", "example", "of", "text", "justification."]
L: 16.
Return the formatted lines as:
[
"This is an",
"example of text",
"justification. "
]
Note: Each word is guaranteed not to exceed L in length.
click to show corner cases.
Corner Cases:
A line other than the last line might contain only one word. What should you do in this case?
In this case, that line should be left-justified.
Hide Company Tags LinkedIn Airbnb
Hide Tags String
*/
package string;
import java.util.*;
public class TextJustification {
public static void main(String[] args) {
String[] words = {"This", "is", "an", "example", "of", "text", "justification."};
int L = 16;
TextJustification tj = new TextJustification();
ArrayList<String> result = tj.fullJustify(words, L);
for (String line : result)
System.out.println(line);
}
// T(len(words)*L), S(len(words)*L)
public ArrayList<String> fullJustify(String[] words, int L) {
ArrayList<String> res = new ArrayList<String>();
int len=0; // count current line char length
int start=0; // count the start index of the word in current line
for(int i=0; i<words.length; i++) {
len +=words[i].length();
if(len+i-start>L){ //i-start means the least spaces we need between words
res.add(justify(words, start, i-1, len-words[i].length(), L));
len=words[i].length(); // reset len
start=i;
}
}
// last line
if(len>0) res.add(justify(words, start, words.length-1, len, L));
if(res.size()==0) res.add(stuffSpaces(L));
return res;
}
// generate a string of Length L, containing words[start...end] inclusively
// T(L), S(L)
private String justify(String[] words, int start, int end, int total, int L){
StringBuilder sb = new StringBuilder();
if(end==start || end==words.length-1){ // single word or last line
while(start<end) sb.append(words[start++]).append(" ");
sb.append(words[end]).append(stuffSpaces(L-sb.length()));
} else {
int space=(L-total)/(end-start);
int extra=(L-total)%(end-start);
while(start<end){
sb.append(words[start++]);
sb.append(stuffSpaces(space));
if(extra>0) {
sb.append(" ");
extra--;
}
}
sb.append(words[end]);
}
return sb.toString();
}
private String stuffSpaces(int n){
if(n==0) return "";
StringBuilder sb = new StringBuilder();
while(n-->0) sb.append(" ");
return sb.toString();
}
}
68. Text Justification
最后編輯于 :
?著作權(quán)歸作者所有,轉(zhuǎn)載或內(nèi)容合作請聯(lián)系作者
【社區(qū)內(nèi)容提示】社區(qū)部分內(nèi)容疑似由AI輔助生成,瀏覽時請結(jié)合常識與多方信息審慎甄別。
平臺聲明:文章內(nèi)容(如有圖片或視頻亦包括在內(nèi))由作者上傳并發(fā)布,文章內(nèi)容僅代表作者本人觀點,簡書系信息發(fā)布平臺,僅提供信息存儲服務(wù)。
【社區(qū)內(nèi)容提示】社區(qū)部分內(nèi)容疑似由AI輔助生成,瀏覽時請結(jié)合常識與多方信息審慎甄別。
平臺聲明:文章內(nèi)容(如有圖片或視頻亦包括在內(nèi))由作者上傳并發(fā)布,文章內(nèi)容僅代表作者本人觀點,簡書系信息發(fā)布平臺,僅提供信息存儲服務(wù)。
相關(guān)閱讀更多精彩內(nèi)容
- Given an array of words and a length L, format the text s...
- 解題思路 這是一個典型的貪心算法,基本思路就是:掃描字符串?dāng)?shù)組,累加長度,當(dāng)發(fā)現(xiàn)長度超過最大長度的時候,就把前面的...
- 題目 Given an array of words and a length L, format the tex...
- 問題 Given an array of words and a length L, format the tex...
- Xamarin XAML語言教程構(gòu)建ControlTemplate控件模板 控件模板ControlTemplate...