簡述
比特幣的歷史
比特幣基本原理
md4 MD5 sha-1 sha-2 hash256 -512 ?sha-3
哈希算法
login as: shizizheng
shizizheng@47.94.19.190's password:
Last login: Sun Apr 15 11:06:22 2018 from 118.26.141.141
Welcome to Alibaba Cloud Elastic Compute Service !
$ nano abc.c
#includechar *get_file(char *path){
? ? ? ? FILE *file;
? ? ? ? int length;
? ? ? ? char *contents;
? ? ? ? file = fopen(path,"r+");
? ? ? ? fseek(file, 0, SEEK_END);
? ? ? ? length = ftell(file);
? ? ? ? fseek(file, 0, SEEK_SET);
? ? ? ? contents = malloc(length+1);
? ? ? ? fread(contents, 1,length,file);
? ? ? ? fclose(file);
? ? ? ? return contents;
}
int main(int count,char **argument)
{
? ? ? ? char *files;
? ? ? ? files = get_file(argument[1]);
? ? ? ? hash_state md;
? ? ? ? unsigned char out[64];
? ? ? ? sha256_init(&md);
? ? ? ? sha256_process(&md,files,strlen(files));
? ? ? ? sha256_done(&md,out);
? ? ? ? for (int i = 0; i < 64; i++)
? ? ? ? {
? ? ? ? ? ? ? ? printf("%x",out[i]);
? ? ? ? }
? ? ? ? return 0;
}
$ nano abc.c
$ tcc abc.c -c -o abc.o
$ tcc abc.o -ltomcrypt -o abcd
$ ./abcd shsh.txt
fa8487d7a2e9e3f73a24ad91d384bb48a65ea997b6c6f3bdc443572618d00000000000000000000000000000000$ ^C
數(shù)字簽名
ecdsa(橢圓曲線數(shù)字簽名算法)
一、ECDSA是什么
1、DSA歷史介紹
加密:RSA, ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? Elgamal ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?,ECC
簽名：RSA-DSA ? ? ? ? ? ? ? ? ? ? ? ?Elgamal-RSA ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?EC-DSA
2、定義
密鑰生成
K={p,q,E,B,mA,B=ma}
Secp256k1:y^2=x^3+7 ?mod ?p
y^2=x^3+ax+b mod p ?a.b屬于Fp
二、為什么采用ECDSA
三、ECDSA在區(qū)塊鏈中的應(yīng)用
1、交易
四、編程實現(xiàn)ECDSA
login as: shizizheng
shizizheng@47.94.19.190's password:
Last login: Sun Apr 15 13:58:37 2018 from 118.26.141.141
Welcome to Alibaba Cloud Elastic Compute Service !
$ nano abc.c
$ nano abcde.c
$ cat abcde.c
int main (int argc, char ** arguement){
? ? ? ? int hash_idx;
? ? ? ? int prng_idx;
? ? ? ? int res, err;
? ? ? ? unsigned long L1, L2;
? ? ? ? unsigned char hash_out[1024],
? ? ? ? ? ? ? ? ? ? ? ? ? out[1024],
? ? ? ? ? ? ? ? ? ? ? sign_out[1024];
? ? ? ? memset(hash_out,0, 1024);
? ? ? ? memset(out, 0, 1024);
? ? ? ? memset(sign_out, 0,1024);
? ? ? ? ecc_key key;
const ltc_ecc_set_type dp[]={32,
? ? ? ? "ECC-256"
? ? ? ? "FFFFFFFF00000001000000000000000000000000FFFFFFFFFFFFFFFFFFFFFFFF",
? ? ? ? "5AC635D8AA3A93E7B3EBBD55769886BC651D06B0CC53B0F63BCE3C3E27D2604B",
? ? ? ? "FFFFFFFF00000000FFFFFFFFFFFFFFFFBCE6FAADA7179E84F3B9CAC2FC632551",
? ? ? ? "6B17D1F2E12C4247F8BCE6E563A440F277037D812DEB33A0F4A13945D898C296",
? ? ? ? "4FE342E2FE1A7F9B8EE7EB4A7C0F9E162BCE33576B315ECECBB6406837BF51F5"
? ? ? ? }
}
命令
$ cp /usr/lib/libtfm.a ~/
$ ls
a? a.out? abc.c? abc.c.save? abc.o? abcd? abcde.c? abcdef.c? libtfm.a? libtomcrypt.a? sha256.o? shsh.txt
$ nano abcdef.c
$
$
$ ls
a? a.out? aaaaa.c? abc.c? abc.c.save? abc.o? abcd? abcde.c? abcdef.c? abcdef.o? libtfm.a? libtomcrypt.a? sha256.o? shsh.txt
$? nano bbb.c
$ cp /home/libtomcrypt.a ~/
$ tcc bbb.c -c -o bbb.o
$ tcc bbb.o libtomcrypt.a libtfm.a -o acc
$ ls
a? a.out? aaaaa.c? abc.c? abc.c.save? abc.o? abcd? abcde.c? abcdef.c? abcdef.o? acc? bbb.c? bbb.o? libtfm.a? libtomcrypt.a? sha256.o? shsh.txt
$ ./acc shsh.txt
fread: 100
signature value: 30452206efb193ff2ec8ffd93f7c732f8a799d139d23dcc97832cbf7ed548c4fdf1352210a5d911978a0fec37392ac126fcbde6e4ccd37eaa52651181c4e819380fe11
return non-value if the signature is valid: 1
$ ^C
$
