Python筆記1

1. list

1.1 reverse a list

  • slicing
lst[::-1]

有返回值,返回一個新的list,原list不變
注:slicing操作都是返回一個新的list

  • reverse( )
lst.reverse( )

返回None,原list翻轉(zhuǎn)

  • reversed()
list(reversed(lst))

返回一個新的list,原list不變
reversed( ) return a "reverse iterator"

1.2 list method

  • append( ) & extend( )
    append( ) 在list后邊添加一個值
    extend( ) 在list后面添加給定的所有值,參數(shù)為list或者tuple (其他seq應(yīng)該也可以)
>>> lst = [1,2]
>>> lst.extend([3,4])
>>> lst
[1, 2, 3, 4]
>>> lst.extend((5,6))
>>> lst
[1, 2, 3, 4, 5, 6]
  • remove(x) & pop([i]) & del
    remove(x)刪除從左邊第一個出現(xiàn)的值為x的元素,如果沒有match的元素,返回error
    pop( )默認(rèn)彈出最后一個元素,也可以指定彈出的index
    del好像并不是list的方法
    del( )刪除指定index的元素,或者一個slice段
    del( )無返回值,pop( )會返回彈出的元素
  • index(x)
  • count(x)
  • sort(cmp=None, key=None, reverse=False)

1.3 stack & queue

  • stack
    直接用append( )和pop( )即可

  • queue
    however, lists are not efficient for this purpose. While appends and pops from the end of list are fast, doing inserts or pops from the beginning of a list is slow (because all of the other elements have to be shifted by one).
    list不適合用來做queue

如果要用queue的話,參考deque

from collections import deque
>>> queue = deque(["Eric", "John", "Michael"])
>>> queue.append("Terry") 
>>> queue.append("Graham") 
>>> queue.popleft()
'Eric'
>>> queue.popleft()
 'John'

1.4 Functional Programming Tools

  • filter(function, sequence):
    給定一個序列,返回sequence中滿足function條件為true的序列

  • map(function, sequence):
    對于sequence中的每個元素,調(diào)用function函數(shù),然后返回值組成一個list

>>> seq = range(8)
>>> def add(x, y): return x+y ...
>>> map(add, seq, seq)
[0, 2, 4, 6, 8, 10, 12, 14]
  • reduce(function, sequence):
    每次sequence中的前兩個元素作為參數(shù)調(diào)用function,返回的結(jié)果與后面一個元素繼續(xù)調(diào)用function,知道sequence結(jié)束
>>> def add(x,y): return x+y 
...
>>> reduce(add, range(1, 11)) 
55

2 其他類型

2.1 tuple

  • tuple不能修改
  • empty tuple: empty = ( )
  • tuple with 1 element: single = 13,
    在末尾加一個逗號

2.2 set

  • set是無序的(unordered)
  • 創(chuàng)建set,用set( )或者{ },{ }不能用來創(chuàng)建空set,{ }會創(chuàng)建一個空的字典
>>> basket = ['apple', 'orange', 'apple', 'pear', 'orange', 'banana'] 
>>> fruit = set(basket) # create a set without duplicates 
>>> fruit
set(['orange', 'pear', 'apple', 'banana'])
  • set可以做集合運算
    -, |, &, ^

2.3 dictionary

  • dictionary的key必須是不可修改的類型,通常為number或者string,tuple也可以 (tuple中不能包含可修改類型,如list)

操作符

  • / 和 //
    如果兩個操作數(shù)都是int,/ 返回類型int,執(zhí)行floor division
    如果任何一個操作數(shù)是float,/ 返回類型float,執(zhí)行正常除法
    // 無論如何都返回floor division,但類型仍然是浮點數(shù)
>>> 3.0 // 2 
1.0

floor division: Mathematical division that rounds down to nearest integer.

Strings

  • ' 和 ‘’ 功能一樣
    ""' 或者 ‘’‘ 用來處理跨行字符串

  • r 代表原始字符串,不轉(zhuǎn)義

>>> print r'C:\some\name'
C:\some\name

在regex時候也常用到

  • string不能修改

shallow copy & deep copy

to be continued

lambda表達(dá)式

to be continued

賦值順序

a, b = b, a+b

the expressions on the right-hand side are all evaluated first before any of the assignments take place. The right-hand side expressions are evaluated from the left to the right.

循環(huán)

循環(huán)中使用else

例子:search for prime numbers

for n in range(2, 10):
    for x in range(2, n):
        if n % x == 0:
            print n, 'equals', x, '*', n/x
            break
    else:
        print n, 'is prime number'

Loop statements may have an else clause; it is executed when the loop terminates through exhaustion of the list (with for) or when the condition becomes false (with while), but not when the loop is terminated by a break statement.

循環(huán)技巧

  • index和value一起循環(huán)
for i, v in enumerate(['a', 'b', 'c']):
    print i, v
  • 循環(huán)dictionary的key和value,用iteritems()
>>> knights = {'gallahad': 'the pure', 'robin': 'the brave'} 
>>> for k, v in knights.iteritems():

參數(shù)

  • 收集參數(shù)
def cheeseshop(kind, *arguments, **keywords):
    print kind
    for arg in arguments:
        print arg
    keys = sort(keywords.keys())
    for key in keys:
        print keywords[key]

* : 收集其余位置的參數(shù),如果不提供任何收集的元素,則為空元組,收集的參數(shù)存儲在tuple中
** : 收集帶有關(guān)鍵字的參數(shù),存儲在dict中

  • unpacking argument list
def parrot(voltage, state='a stiff', action='voom'):
    print "-- This parrot wouldn't", action,
    print "if you put", voltage, "volts through it.",
    print "E's", state, "!"
# 
d = {"voltage": "four million", "state": "bleedin' demised", "action": "VOOM"}
parrot(**d)
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