#include<iostream>
#include<cmath>
using namespace std;
typedef long long LL;
LL a, b;
int d;
int main()
{
    scanf("%lld%lld%d", &a, &b, &d);
    LL c = a + b;
    int num[1000], cnt = 0;
    do {
        num[cnt++] = c % d;
        c/=d;
    } while (c);
    for (int i = cnt - 1; i >= 0; i--)
    {
        printf("%d", num[i]);
    }
    return 0;
}